Chapter 10.1, Problem 4GP

To determine

To find: The measure of center best represents the data.

Answer to Problem 4GP

The Mean is best center to represent the data and measure of centre is $43.5$ .

Explanation of Solution

Given information: The students of different eighth grade homerooms read $38,45,26,51,42,38,50,58$ books for a reading competition.

Calculation: The students of different eighth grade homerooms read $38,45,26,51,42,38,50,58$ books for a reading competition.

Mean of data is:

  $\begin{array}{l}\mathrm{Mean}=\frac{sumofdata}{\mathrm{number}\mathrm{of}\mathrm{data}}\\ \mathrm{Mean}=\frac{38+45+26+51+42+38+50+58}{8}=\frac{348}{8}=43.5\end{array}$

The data has no extreme values, gaps, or repeated values. So the mean is more appropriate here.

Thus, the measure of center is $43.5$ .