Chapter 10.1, Problem 7IP

To determine

To find: The mean, mode and median of the data.

Answer to Problem 7IP

The Mean is $245$ , Median is $243$ and Mode is $200$ .

Explanation of Solution

Given information: The prices in dollars of digital cameras are $250,200,320,235,265,200$ .

Calculation: The prices in dollars of digital cameras are $250,200,320,235,265,200$ .

Mean of data is:

  $\begin{array}{l}\mathrm{Mean}=\frac{sumofdata}{\mathrm{number}\mathrm{of}\mathrm{data}}\\ \mathrm{Mean}=\frac{250+200+320+235+265+200}{6}=\frac{1470}{6}=245\end{array}$

Median of the data:

Data in ascending order $200,200,235,250,265,320$ .

  $\begin{array}{l}\mathrm{n}=6\\ \mathrm{Median}=\frac{\frac{n}{2}\mathrm{th}+(\frac{n}{2}+1)\mathrm{th}}{2}=\frac{(\frac{6}{2})\mathrm{th}+(\frac{6}{2}+1)\mathrm{th}}{2}=\frac{3\mathrm{rd}+4\mathrm{th}}{2}=\frac{235+250}{2}=\frac{485}{2}=242.5\\ \mathrm{Round}off(242.5)=243\end{array}$

So median is $243$ .

Mode:

In this case, $200$ are more frequent. So mode $200$ .

Thus, the Mean is $245$ , Median is $243$ and Mode is $200$ .