Chapter 10.7, Problem 22CCR

To determine

To find: The probability as a fraction and as a percent.

Answer to Problem 22CCR

The probability in fraction is $\frac{1}{6}$ .

The probability in percent is $16.66\%$ .

Probability of the event is unlikely to occur.

Explanation of Solution

Given information: A spinner is given in figure is spun once.

Calculation: A spinner is given in figure is spun once..

The sample space is $\left\{A,J,M,E,W,P\right\}$ .

Total outcomes $=6$ .

Favourable outcomes $=\left\{A\right\}$ .

Number of favourable outcomes $=1$ .

  $\mathrm{P}(\mathrm{event})=\frac{\mathrm{number}\mathrm{of}\mathrm{favourable}\mathrm{outcomes}}{\mathrm{number}\mathrm{of}\mathrm{total}\mathrm{outcomes}}$

  $\begin{array}{l}\mathrm{P}(A)=\frac{1}{6}\\ \mathrm{In}\mathrm{percent}=\frac{1}{6}\times 100\%=\frac{1}{3}\times 50\%=\frac{50}{3}\%=16.66\%\end{array}$

Probability of event is less than $50\%$ , So the event is unlikely to occur.

Thus, the probability in fraction is $\frac{1}{6}$ ,the in percent is $16.66\%$ and probability of the event is unlikely to occur.