Chapter 10.1, Problem 25STP

To determine

To Find: To find the frequency such that the average must be same.

Answer to Problem 25STP

The answer is 140.

Explanation of Solution

Given information:Scores in different games

Formula used:

  $\text{For}\text{Mean}=\frac{\text{Total}\text{number}\text{of}\text{observation}}{\text{Number}\text{of}\text{observation}}$ .

Calculation:

Calculation of mean

  $\begin{array}{l}\text{Mean}=\frac{124+135+109+116+141+155}{6}\\ \text{Mean}=\frac{780}{6}\\ \therefore \text{Mean}=130\end{array}$

Thus, mean of the given game is 130.

Let the score in sixth game is x

Since mean is 130

  $\begin{array}{l}\therefore \text{Mean}=\frac{125+132+128+130+125+x}{6}\\ 130\times 6=640+x\\ 780-640=x\\ x=140\end{array}$

Hencethe score in sixth game is 140.