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Science Chemistry EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M

The structure of bromide formed from the treatment of exo − Norborneol with concentrated HBr should be written and its mechanism should be proposed with the curved arrows. The reason behind the formation of single diastereomer should be written. Concept introduction: Hydration of norbornene proceeds via norbornyl cation intermediate. This cation can be attacked from two positions. If the water attacks from above so that hydroxyl group ends up in above side it leads to exo − Norborneol while if the water attacks from beneath so that hydroxyl group ends up in below side it leads to endo − Norborneol illustrated as follows:

The structure of bromide formed from the treatment of exo − Norborneol with concentrated HBr should be written and its mechanism should be proposed with the curved arrows. The reason behind the formation of single diastereomer should be written. Concept introduction: Hydration of norbornene proceeds via norbornyl cation intermediate. This cation can be attacked from two positions. If the water attacks from above so that hydroxyl group ends up in above side it leads to exo − Norborneol while if the water attacks from beneath so that hydroxyl group ends up in below side it leads to endo − Norborneol illustrated as follows:

Solution Summary: The author proposes that the structure of bromide formed from the treatment of exo- Norborneol should be written and its mechanism with the curved arrows.

EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M

EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M

6th Edition

ISBN: 9781305687875

Author: Gilbert

Publisher: CENGAGE LEARNING - CONSIGNMENT

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Question

Chapter 10.7, Problem 8E

Interpretation Introduction

Interpretation:The structure of bromide formed from the treatment of exo−Norborneol with concentrated HBr should be written and its mechanism should be proposed with the curved arrows. The reason behind the formation of single diastereomer should be written.

Concept introduction:Hydration of norbornene proceeds via norbornyl cation intermediate. This cation can be attacked from two positions. If the water attacks from above so that hydroxyl group ends up in above side it leads to exo−Norborneol while if the water attacks from beneath so that hydroxyl group ends up in below side it leads to endo−Norborneol illustrated as follows:

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Chapter 10.7, Problem 7E

Chapter 10.7, Problem 9E

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Chapter 10 Solutions

EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M

Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E

Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.3 - Prob. 1E Ch. 10.3 - Prob. 2E Ch. 10.3 - Prob. 3E Ch. 10.3 - Prob. 4E Ch. 10.3 - Prob. 5E Ch. 10.3 - Prob. 6E Ch. 10.3 - Prob. 7E Ch. 10.3 - Prob. 8E Ch. 10.3 - Prob. 9E Ch. 10.3 - Prob. 10E Ch. 10.3 - Prob. 11E Ch. 10.3 - Prob. 12E Ch. 10.3 - Prob. 13E Ch. 10.3 - Prob. 14E Ch. 10.3 - Prob. 15E Ch. 10.3 - Prob. 16E Ch. 10.3 - Prob. 17E Ch. 10.3 - Prob. 18E Ch. 10.3 - Prob. 19E Ch. 10.3 - Prob. 20E Ch. 10.3 - Prob. 21E Ch. 10.3 - Prob. 22E Ch. 10.3 - Prob. 23E Ch. 10.3 - Prob. 24E Ch. 10.3 - Prob. 25E Ch. 10.3 - Prob. 26E Ch. 10.3 - Prob. 27E Ch. 10.3 - Prob. 28E Ch. 10.3 - Prob. 29E Ch. 10.3 - Prob. 30E Ch. 10.3 - Prob. 31E Ch. 10.3 - Prob. 32E Ch. 10.5 - Prob. 1E Ch. 10.5 - Prob. 2E Ch. 10.5 - Prob. 3E Ch. 10.5 - Prob. 4E Ch. 10.5 - Prob. 5E Ch. 10.5 - Prob. 6E Ch. 10.5 - Prob. 7E Ch. 10.5 - Prob. 8E Ch. 10.5 - Prob. 9E Ch. 10.5 - Prob. 10E Ch. 10.5 - Prob. 11E Ch. 10.5 - Prob. 12E Ch. 10.5 - Prob. 14E Ch. 10.5 - Prob. 15E Ch. 10.5 - Prob. 16E Ch. 10.5 - Prob. 17E Ch. 10.5 - Prob. 18E Ch. 10.5 - Prob. 19E Ch. 10.5 - Prob. 20E Ch. 10.5 - Prob. 23E Ch. 10.6 - Prob. 1E Ch. 10.6 - Prob. 2E Ch. 10.6 - Prob. 3E Ch. 10.6 - Prob. 4E Ch. 10.6 - Prob. 5E Ch. 10.6 - Prob. 6E Ch. 10.6 - Prob. 7E Ch. 10.6 - Prob. 8E Ch. 10.6 - Prob. 9E Ch. 10.6 - Prob. 10E Ch. 10.6 - Prob. 11E Ch. 10.6 - Prob. 12E Ch. 10.6 - Prob. 13E Ch. 10.6 - Prob. 14E Ch. 10.6 - Prob. 15E Ch. 10.6 - Prob. 16E Ch. 10.6 - Prob. 17E Ch. 10.6 - Prob. 18E Ch. 10.6 - Prob. 20E Ch. 10.6 - Prob. 21E Ch. 10.6 - Prob. 22E Ch. 10.6 - Prob. 23E Ch. 10.6 - Prob. 24E Ch. 10.6 - Prob. 25E Ch. 10.6 - Prob. 26E Ch. 10.6 - Prob. 28E Ch. 10.6 - Prob. 29E Ch. 10.6 - Prob. 30E Ch. 10.7 - Prob. 1E Ch. 10.7 - Prob. 2E Ch. 10.7 - Prob. 3E Ch. 10.7 - Prob. 4E Ch. 10.7 - Prob. 5E Ch. 10.7 - Prob. 6E Ch. 10.7 - Prob. 7E Ch. 10.7 - Prob. 8E Ch. 10.7 - Prob. 9E Ch. 10.7 - Prob. 10E Ch. 10.7 - Prob. 11E Ch. 10.7 - Prob. 12E Ch. 10.8 - Prob. 1E Ch. 10.8 - Prob. 2E Ch. 10.8 - Prob. 4E Ch. 10.8 - Prob. 5E Ch. 10.8 - Prob. 6E Ch. 10.8 - Prob. 7E Ch. 10.8 - Prob. 8E Ch. 10.8 - Prob. 9E Ch. 10.8 - Prob. 10E Ch. 10.8 - Prob. 11E Ch. 10.8 - Prob. 12E Ch. 10.8 - Prob. 13E Ch. 10.8 - Prob. 14E Ch. 10.8 - Prob. 15E

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