In the radical chlorination of methane, one propagation step is shown as
Why do we eliminate the possibility that this step goes as shown below?
(a) Because in the next propagation step, H· would have to react with Cl2 to form Cland HCl; this reaction is not feasible.
(b) Because this alternative step has a more endothermic ΔH° than the first.
(c) Because free hydrogen atoms cannot exist.
(d) Because this alternative step is not consistent with the high photochemical efficiency of this reaction.
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