Organic Chemistry
11th Edition
ISBN: 9781118133576
Author: T. W. Graham Solomons, Craig Fryhle
Publisher: Wiley, John & Sons, Incorporated
expand_more
expand_more
format_list_bulleted
Question
Chapter 10, Problem 21P
Interpretation Introduction
Interpretation: The chain-initiating and chain-propagating steps showing the formation of the products in the given reaction are to given.
Concept Introduction:
A free radical halogenation reaction is a type of reaction in which thereplacement of hydrogen atom with a bromine atom in the moleculetakes place in the presence of UV light. It is a type of a halogenation reaction.
Molecules that have one unpaired electron are called free radicals.
A
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Alkenes can be hydrated to form alcohols by (1) hydroboration followed by oxidation with alkaline hydrogen peroxide and (2) acid-catalyzed hydration. Compare the product formed from each alkene by sequence (1) with those formed from (2).
Q.)1-Methylcyclohexene
The relative rates of reaction of ethane, toluene, and ethylbenzene with bromine atoms have
been measured. The most reactive hydrocarbon undergoes hydrogen atom abstraction a million times
faster than does the least reactive one. Arrange these hydrocarbons order of decreasing reactivity.
Organic chemistry - Alcohols
Chapter 10 Solutions
Organic Chemistry
Ch. 10 - Prob. 1PPCh. 10 - Prob. 2PPCh. 10 - Practice Problem 10.3 How would the molecular ion...Ch. 10 - Prob. 4PPCh. 10 - Prob. 5PPCh. 10 - Prob. 6PPCh. 10 - Practice Problem 10.7 Chlorination reactions of...Ch. 10 - Prob. 8PPCh. 10 - Prob. 9PPCh. 10 - Prob. 10PP
Ch. 10 - Prob. 11PPCh. 10 - Practice Problem 10.12 Benzylic radicals, due to...Ch. 10 - Prob. 13PPCh. 10 - Practice Problem 10.14 Show how the following...Ch. 10 - Prob. 15PPCh. 10 - Prob. 16PPCh. 10 - Prob. 17PPCh. 10 - Prob. 18PCh. 10 - Explain the relative distribution of produces...Ch. 10 - 10.20 Which of the following compounds can be...Ch. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - 10.25 List in order of decreasing stability all of...Ch. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Starting with the compound or compounds indicated...Ch. 10 - Prob. 30PCh. 10 - 10.31 Synthesize each of the following compounds...Ch. 10 - 10.32 Synthesize each of the following compounds...Ch. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Write a mechanism for the following reaction.Ch. 10 - Prob. 37PCh. 10 - The halogen atom of an alkyl halide can be...Ch. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - If one were to try to draw the simplest Lewis...Ch. 10 - Prob. 1LGPCh. 10 - 2. (a) Propose a synthesis of 2-methoxypropene...Ch. 10 - Use the single-bond dissociation energies of Table...Ch. 10 - 10.2 In the radical chlorination of methane, one...Ch. 10 - Prob. 3QCh. 10 - Use the single-bond dissociation energies of Table...Ch. 10 - Prob. 5QCh. 10 - Prob. 6Q
Knowledge Booster
Similar questions
- describe about the stability of some compounds ( provide some examples) and intermediates such as double bonds (Zaitsev rule), carbocations, carbanions, and carbenes.arrow_forwardSynthesize from benzene. (Hint: All of these require diazonium ions.) ) 3-n-propylphenolarrow_forwardEthane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below.CH3CH3+ Cl2→ CH3CH2Cl+ HClDescribe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish.arrow_forward
- Free-radical chlorination of hexane gives very poor yields of 1-chlorohexane, while cyclohexane can be converted to chlorocyclohexane in good yield. What ratio of reactants (cyclohexane and chlorine) would you use for the synthesis of chlorocyclohexane?arrow_forwardThe heat of combustion of decahydronaphthalene(C10H18) is -6286 kJ/mol. The heat of combustion ofnaphthalene (C10H8) is -5157 kJ/mol. (In both casesCO2(g) and H2O(l) are the products.) Calculate the heat of hydrogenationand the resonance energy of naphthalene.arrow_forwardFree‑radical halogenation can occur with chlorine and a source of direct UV radiation or sunlight. Chlorination of 2,4‑dimethylpentane via radical halogenation leads to the formation of all three of the products shown. Estimate the relative percentages of each product that will be formed using this means of halogenation. Presume that 1 equivalent of chlorine is used.arrow_forward
- МЕСНANISMS 1,2-epoxy-1-methylcyclopentane undergoes both acid-catalyzed and base-catalyzed opening of the epoxide ring to form two different products. > Using ethanol as the solvent and an appropriate acid, show the steps in the acid catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). > Using ethanol as the solvent and an appropriate base, show the steps in the base- catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). 1,2-epoxy-1-methylcyclopentane CH3arrow_forwardSubstitutions on aromatic rings are generally carried out by electrophilic substitution, but for the synthesis of phenolic compounds and alkoxy benzene it is carried out by nucleophilic substitution, explain why this is so .arrow_forwardAlkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions -X티 Hö: H-O -CH3 -CH3 H30*arrow_forward
- The rate law for addition of Br2 to an alkene is first orderin Br2 and first order in the alkene. Does this informationsuggest that the mechanism of addition of Br2 to analkene proceeds in the same manner as for addition of HBr?Explain.arrow_forwardThe compound below is treated with chlorine in the presence of light. CH3 CH3CHCH₂CH3 Draw the structure for the organic radical species produced by reaction of the compound with a chlorine atom. Assume reaction occurs at the weakest C-H bond. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. n [ ]# ?arrow_forwardExplain the role strain plays on stability and reactivity of a cyclic alkane such as cyclopropane.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning