Organic Chemistry
11th Edition
ISBN: 9781118133576
Author: T. W. Graham Solomons, Craig Fryhle
Publisher: Wiley, John & Sons, Incorporated
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Textbook Question
Chapter 10, Problem 1Q
Use the single-
TABLE 10.1 Single-bond homolytic dissociation energies DH° at 25°C
10.1 On the basis of Table Q10.1, what is the order of decreasing stability of the radicals,
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Find the AHn for the following reaction:
B2H6 (g) + 6 Cl2(9) → 2 BC13(g) + 6 HC(9)
given the following reactions and subsequent AH° values
$$
H3 BO3 (g) + 3 HC((g)
ΔΗ'-
-113.1 kJ
BC13 (g) + 3 H20(1) →
B2 H6 + 6 H2O(1) → 2 H3 BO3(9) + 6 H2 (9)
AH° = -496 kJ
1
HC(g)
AH° = -95.5 kJ
(6)1 + (6)H?
$$
Find the deltaH for the reaction below, given the following reactions and subsequent deltaH values: N2H4(l) + H2(g) —> 2NH3 (g)
N2H4(l) + CH4O(l) —> CH2O (g) + N2(g) + 3H2(g)—— deltaH= -32.8kj
N2(g)+ 3H2(g) —> 2NH3 (g)—deltaH=-57.2 kj
CH4O(l) —>CH2O(g) + H2(g) —-deltaH= -65 kj
SIG FIGS
Compound
∆Hf (kJ/mole)
∆S (J/mole K)
CO2(g)
–393.5
+213.8
CO2 (aq)
–413.8
+117.6
N2O4
9.16
+304.4
NO2
33.2
240.1
CaCO3
–1207.6
91.7
CaO
–634.9
+38.1
I2 (g)
62.42
260.69
HI(g)
26.5
206.6
H2 (g)
0
130.7
(a) For the following reactions, using the provided ∆H and ∆S data, determine
whether each one would be spontaneous or nonspontaneous at 25°C CO2(g) à CO2(aq)
N2O4(g)-------- à2 NO2(g)
CaCO3(s) ----à CaO (s) + CO2(g)
H2 (g) + I2(g)---- à 2 HI (g)
Chapter 10 Solutions
Organic Chemistry
Ch. 10 - Prob. 1PPCh. 10 - Prob. 2PPCh. 10 - Practice Problem 10.3 How would the molecular ion...Ch. 10 - Prob. 4PPCh. 10 - Prob. 5PPCh. 10 - Prob. 6PPCh. 10 - Practice Problem 10.7 Chlorination reactions of...Ch. 10 - Prob. 8PPCh. 10 - Prob. 9PPCh. 10 - Prob. 10PP
Ch. 10 - Prob. 11PPCh. 10 - Practice Problem 10.12 Benzylic radicals, due to...Ch. 10 - Prob. 13PPCh. 10 - Practice Problem 10.14 Show how the following...Ch. 10 - Prob. 15PPCh. 10 - Prob. 16PPCh. 10 - Prob. 17PPCh. 10 - Prob. 18PCh. 10 - Explain the relative distribution of produces...Ch. 10 - 10.20 Which of the following compounds can be...Ch. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - 10.25 List in order of decreasing stability all of...Ch. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Starting with the compound or compounds indicated...Ch. 10 - Prob. 30PCh. 10 - 10.31 Synthesize each of the following compounds...Ch. 10 - 10.32 Synthesize each of the following compounds...Ch. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Write a mechanism for the following reaction.Ch. 10 - Prob. 37PCh. 10 - The halogen atom of an alkyl halide can be...Ch. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - If one were to try to draw the simplest Lewis...Ch. 10 - Prob. 1LGPCh. 10 - 2. (a) Propose a synthesis of 2-methoxypropene...Ch. 10 - Use the single-bond dissociation energies of Table...Ch. 10 - 10.2 In the radical chlorination of methane, one...Ch. 10 - Prob. 3QCh. 10 - Use the single-bond dissociation energies of Table...Ch. 10 - Prob. 5QCh. 10 - Prob. 6Q
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- Cubane (C8H8; see structure below) is an organic hydrocarbon containing eight carbon atoms located at the vertices of a cube. While attempts to synthesis this molecule have been successful, it rapidly decomposes at room temperature. Using your knowledge of organic structure, suggest a reasonable explanation for the energetic instability of cubanearrow_forwardPolyvinyl chloride (PVC) is one of the most commercially important polymers. PVC is made by addition polymerization of vinyl chloride (C2 H3 Cl). Vinyl chloride is synthesized from ethylene (C2 H4) in a two-step process involving the following equilibria: Selected bond dissociation enthalpies are given in this table. Dissociation enthalpy (kJ/mol) Equilibrium 1: C2 H4(g) + Cl2 (g) = C2H4C12 (g) • Equilibrium 2: C2H4C12 (g) = C2H3C1(g) + HC1(g) Bond C-C 348 C=C 614 Part A C=C 839 C-C1 328 What are the C-C bond orders in C2H4 Cl2 and C2 H3 Cl, respectively? C-H 413 Express your answers numerically separated by commas. Cl-Cl 242 • View Available Hint(s) Н-Н 436 H-Cl 431 Submitarrow_forward2. Given the following data: CO(g)+H2O(g)→ CO2(g)+ H2(g) AH (25° C) = -42.0 kJmol1 Cp (CO) = 26.8 + 6 x 10³T JK'mol1 Cp (H2O) = 30.1 + 10 x 10³T JK'mol1 Cp (H2) = 28.5 + 2 x 10³T JK-'mol-1 Cp (CO2) = 26.4 + 42 x 10³T JK-'mol-1 where T is the thermodynamic temperature, calculate the change in enthalpy for the reaction at 1000 K.arrow_forward
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