Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 10, Problem 24P
A boy with Down syndrome (trisomy
Explain how this is possible.
How many chromosomes do you expect to see in karyotypes of the parents?
What term best describes this kind of chromosome abnormality?
What is the probability the next child of this couple will have a normal phenotype and have
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Chapter 10 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 10 - 10.1 Give descriptions for the following...Ch. 10 - 10.2 The human genome contains contains base...Ch. 10 - In eukaryotic DNA, Where are you most likely to...Ch. 10 - 10.4 Describe the importance of light and dark G...Ch. 10 - Human late prophase karyotypes have about 2000...Ch. 10 - Prob. 6PCh. 10 - From the following list, identify the types...Ch. 10 - 10.8 If the haploid number for a plant species is...Ch. 10 - Mating between a male donkey (2n=64) and a female...Ch. 10 - A researcher interested in studying a human gene...
Ch. 10 - 10.11 In what way does position effect variegation...Ch. 10 - 10.12 A pair of homologous chromosomes in...Ch. 10 - 10.13 An animal heterozygous for a reciprocal...Ch. 10 - Dr. Ara B. Dopsis has an idea he thinks will be a...Ch. 10 - A normal chromosome and its homolog carrying a...Ch. 10 - The accompanying chromosome diagram represents a...Ch. 10 - 10.17 Histone protein isolated from pea plants...Ch. 10 - 10.18 A survey of organisms living deep in the...Ch. 10 - In humans that XX/XO mosaics, the phenotype is...Ch. 10 - 10.20 A plant breeder would like to develop the...Ch. 10 - In Drosophilia, seven partial deletion (1to7)...Ch. 10 - Two experimental varieties of strawberry are...Ch. 10 - 10.23 In the tomato, Solanum esculentum, tall ()...Ch. 10 - A boy with Down syndrome (trisomy 21) has 46...Ch. 10 - Experimental evidence demonstrates that the...Ch. 10 - Prob. 26PCh. 10 - Genomic DNA from the nematode worm...Ch. 10 - 10.28 A small population of deer living on an...Ch. 10 - A eukaryote with a diploid number of 2n=6 carries...Ch. 10 - Prob. 30PCh. 10 - For the following crosses, determine as accurately...Ch. 10 - A healthy couple with a history of three previous...
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- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardA boy with Down syndrome (trisomy 21) has 46 chromosomes. One parent and his two older sisters have a normal phenotype, but each have 45 chromosomes. a)Explain how this is possible. b)How many chromosomes do you expect to see in karyotypes of the parents? c)What term best describes this kind of chromosome abnormality? d)What is the probability the next child of this couple will have a normal phenotype and have 46 chromosomes? Explain your answer.arrow_forwardImagine a germ cell for an animal that is 2n=4. Gene A and B are found on chromosome one, and the cell is homozygous for A(AA) and heterozygous for Bb. Gene D is found on chromosome 2 and the germ cell is heterozygous for the Allee of the gene (Dd). Meiosis for this germ cell results in the following four gametes, and one crossing over event during meiosis ABD, ABd, AbD, Abd. Draw the chromosomes in cell during metaphase of meiosis 1. Make sure to include chromosomes, the allele in the correct locations on the chromosomes AFTER the crossing over event, and spindle fibers.arrow_forward
- Part of the karyotype of a diploid individual who is heterozygous for one chromosomal rearrangement is shown in the diagram. The chromosomes involved in the rearrangement, and their homologous pair, are shown. The location of each gene is labeled using horizontal lines and the name of each gene is labeled using letters or numbers. Answer the following questions about the diagram. A. What rearrangement is shown? Be as specific as possible. B. Describe a mutation scenario that could cause this rearrangement to be formed. A B D E F G H IXI A B с D E IIXDD 1 2 3 4 5 6 F G H D 1 2 34 5 6 Xarrow_forwardIn the fruit fly Drosophila melanogaster, a recessive condition called eyeless (ey) significantly interferes with normal eye development. Eyes are either very small or absent. The ey gene is found on chromosome 4, which is the smallest of the four chromosomes in the organism. Individuals with a single copy or three copies of chromosome 4 are viable and can reproduce. A trisomic wild-type male is crossed with a disomic wild-type female: see attached image Determine the chromosome constitution and phenotypic ratios in the offspring. Assume random segregation of chromosomes into gametes.arrow_forwardDescribe the imbalance in gene products that occurs in an individual with monosomy 2.arrow_forward
- We say that genes that are close together on the same chromosome are linked. What does that mean? Imagine that in a diploid nucleus, one chromosome has the allele R and right next to it on the same chromosome is the allele T for a different gene. Are these linked? Imagine that r is right next to t on the homologous chromosome. If this cell never undergoes meiosis, does this matter at all? If it does undergo meiosis, what are the two genotypes that the gametes are most likely to have? Look at Figure for help if you need it.arrow_forwardA phenotypically normal individual has the following combinations of normal and abnormal chromosomes:The normal chromosomes are shown on the left in each pair.Suggest a series of events (breaks, translocations, crossovers, etc.)that may have produced this combination of chromosomes.arrow_forwardDraw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.arrow_forward
- Explain how an individual can have Down's Syndrome, and a karyotype that reveals 46 chromosomes. Group of answer choices The individual has an inversion on chromosome 21. The individual is trisomic for chromosome 21. The individual has one chromosome that is the result of a translocation. The individual is monosomic for chromosome 21. None of these is correct.arrow_forwardGiven that a human normally contains 46 chromosomes, give the chromosome number for each of the following conditions: Turner syndrome (female, no Barr bodies): Klinefelter syndrome (male, one Barr body): Triploid: Down syndrome (trisomic): Trisomy 13:arrow_forwardIn a sample of 1000 patients with Down syndrome, a geneticist discovers that 95% of them are trisomic, while 5% have diploid number of chromosomes. Explain this discrepancy.arrow_forward
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