International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN: 9781305501607
Author: Andrew Pytel And Jaan Kiusalaas
Publisher: CENGAGE L
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Chapter 10, Problem 10.46P
The uniform bar AB of weight W and length L is pinned to a sliding collar at A and to the sliding rod BD at B. The spring wound around rod BD has a stiffness k and is undeformed when rod AB is in the position
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A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35)
200 = 139.3 + 35c₂
200 - 139.3 = 35c₂
60.7 = 35c₂
c₂ = 60.7/35
Short spring (c₂) = 1.73 N/mm
According to my study book, the correct answer is 4.82N/mm
What is wrong with the calculating?
What is the reason for this composition?
Homework: ANOVA Table for followed design
B
AB
Dr
-1
-1
1
(15.18,12)
1
-1
-1
(45.48.51)
-1
1
-1
(25,28,19)
1
1
(75.75,81)
Chapter 10 Solutions
International Edition---engineering Mechanics: Statics, 4th Edition
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