EBK PRACTICE OF STAT.F/AP EXAM,UPDATED
6th Edition
ISBN: 9781319287573
Author: Starnes
Publisher: MPS PUB
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Question
Chapter 1, Problem T1.4SPT
To determine
To find: the following could be the median age.
Expert Solution & Answer

Answer to Problem T1.4SPT
24 years
Explanation of Solution
Given:
Calculation:
Finding the frequency associating to each bar in the histogram
Age of home (yr) | Frequency | C.F. |
5-10 | 7 | 7 |
10-15 | 8 | 15 |
15-20 | 9 | 24 |
20-25 | 7 | 31 |
25-30 | 6 | 37 |
30-35 | 3 | 40 |
35-40 | 4 | 44 |
40-45 | 2 | 46 |
45-50 | 1 | 47 |
50-55 | 1 | 48 |
55-60 | 0 | 48 |
60-65 | 3 | 51 |
65-70 | 0 | 51 |
70-75 | 1 | 52 |
total | 52 |
The median is the mid value of the ascending sorted data set. It is containing 52 data values and therefore the median would be between the middle between the 26th and 27th data values. So
The answer is 24; the reason is that it is between 20 and 25
Hence, the correct option is (c)
Chapter 1 Solutions
EBK PRACTICE OF STAT.F/AP EXAM,UPDATED
Ch. 1.1 - Prob. 11ECh. 1.1 - Prob. 12ECh. 1.1 - Prob. 13ECh. 1.1 - Prob. 14ECh. 1.1 - Prob. 15ECh. 1.1 - Prob. 16ECh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20E
Ch. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.2 - Prob. 50ECh. 1.2 - Prob. 51ECh. 1.2 - Prob. 52ECh. 1.2 - Prob. 53ECh. 1.2 - Prob. 54ECh. 1.2 - Prob. 55ECh. 1.2 - Prob. 56ECh. 1.2 - Prob. 57ECh. 1.2 - Prob. 58ECh. 1.2 - Prob. 59ECh. 1.2 - Prob. 60ECh. 1.2 - Prob. 61ECh. 1.2 - Prob. 62ECh. 1.2 - Prob. 63ECh. 1.2 - Prob. 64ECh. 1.2 - Prob. 65ECh. 1.2 - Prob. 66ECh. 1.2 - Prob. 67ECh. 1.2 - Prob. 68ECh. 1.2 - Prob. 69ECh. 1.2 - Prob. 70ECh. 1.2 - Prob. 71ECh. 1.2 - Prob. 72ECh. 1.2 - Prob. 73ECh. 1.2 - Prob. 74ECh. 1.2 - Prob. 75ECh. 1.2 - Prob. 76ECh. 1.2 - Prob. 77ECh. 1.2 - Prob. 78ECh. 1.2 - Prob. 79ECh. 1.2 - Prob. 80ECh. 1.2 - Prob. 81ECh. 1.2 - Prob. 82ECh. 1.2 - Prob. 83ECh. 1.2 - Prob. 84ECh. 1.2 - Prob. 85ECh. 1.2 - Prob. 86ECh. 1.3 - Prob. 87ECh. 1.3 - Prob. 88ECh. 1.3 - Prob. 89ECh. 1.3 - Prob. 90ECh. 1.3 - Prob. 91ECh. 1.3 - Prob. 92ECh. 1.3 - Prob. 93ECh. 1.3 - Prob. 94ECh. 1.3 - Prob. 95ECh. 1.3 - Prob. 96ECh. 1.3 - Prob. 97ECh. 1.3 - Prob. 98ECh. 1.3 - Prob. 99ECh. 1.3 - Prob. 100ECh. 1.3 - Prob. 101ECh. 1.3 - Prob. 102ECh. 1.3 - Prob. 103ECh. 1.3 - Prob. 104ECh. 1.3 - Prob. 105ECh. 1.3 - Prob. 106ECh. 1.3 - Prob. 107ECh. 1.3 - Prob. 108ECh. 1.3 - Prob. 109ECh. 1.3 - Prob. 110ECh. 1.3 - Prob. 111ECh. 1.3 - Prob. 112ECh. 1.3 - Prob. 113ECh. 1.3 - Prob. 114ECh. 1.3 - Prob. 115ECh. 1.3 - Prob. 116ECh. 1.3 - Prob. 117ECh. 1.3 - Prob. 118ECh. 1.3 - Prob. 119ECh. 1.3 - Prob. 120ECh. 1.3 - Prob. 121ECh. 1.3 - Prob. 122ECh. 1.3 - Prob. 123ECh. 1.3 - Prob. 124ECh. 1.3 - Prob. 125ECh. 1.3 - Prob. 126ECh. 1.3 - Prob. 127ECh. 1.3 - Prob. 128ECh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 5ECh. 1 - Prob. 6ECh. 1 - Prob. 7ECh. 1 - Prob. 8ECh. 1 - Prob. 9ECh. 1 - Prob. 10ECh. 1 - Prob. R1.1RECh. 1 - Prob. R1.2RECh. 1 - Prob. R1.3RECh. 1 - Prob. R1.4RECh. 1 - Prob. R1.5RECh. 1 - Prob. R1.6RECh. 1 - Prob. R1.7RECh. 1 - Prob. R1.8RECh. 1 - Prob. R1.9RECh. 1 - Prob. R1.10RECh. 1 - Prob. T1.1SPTCh. 1 - Prob. T1.2SPTCh. 1 - Prob. T1.3SPTCh. 1 - Prob. T1.4SPTCh. 1 - Prob. T1.5SPTCh. 1 - Prob. T1.6SPTCh. 1 - Prob. T1.7SPTCh. 1 - Prob. T1.8SPTCh. 1 - Prob. T1.9SPTCh. 1 - Prob. T1.10SPTCh. 1 - Prob. T1.11SPTCh. 1 - Prob. T1.12SPTCh. 1 - Prob. T1.13SPTCh. 1 - Prob. T1.14SPT
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