The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined. Concept Introduction: Energy separation between the levels can be calculated using following equation. E n 2 − E n 1 = ( n 2 2 − n 1 2 ) h 2 8 m L 2 = h ν The frequency ( ν ) , wavelength ( λ ) and velocity of light ( c ) are related by following equation. λ = c ν

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Answer 1

Question

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

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Answer 2

Question

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

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Answer 3

Question

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

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Answer 4

Question

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

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Answer 5

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

Answer 6

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

Answer 7

Chapter 1, Problem 1C.2E

(a)

Interpretation Introduction

Interpretation:

The wavelength for the transition for helium atom from forth energy level to first energy level has to be determined.

Concept Introduction:

Energy separation between the levels can be calculated using following equation.

En2 − En1 = (n22−n12)h28mL2=hν

The frequency (ν), wavelength (λ) and velocity of light (c) are related by following equation.

λ = cν

Answer 8

(a)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.192 nm.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Transition is taking place from forth energy level to first energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E1 = 15h28mL2=hν15h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL215h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)215×(6.626×10−34J.s)= 2.192×10−9m= 2.192 nm.

Wavelength is 2.192 nm.

Answer 13

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

Answer 14

(b)

Interpretation Introduction

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

Answer 15

(b)

Expert Solution

Answer to Problem 1C.2E

The wavelength for the transition for helium atom is 2.74 nm.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Transition is taking place from forth energy level to second energy level.

The length of the box is given as 100 pm.

The energy difference for the transition is given below.

En2 − En1 = (n22−n12)h28mL2=hνE4 − E2 = 12h28mL2=hν12h8mL2=ν

Therefore the wavelength can be calculated as follows,

λ=cνλ=8mcL212h=8(9.10939×10−31kg)×(2.988×108m/s)(10−10m)212×(6.626×10−34J.s)= 2.74×10−9m= 2.74 nm.

Wavelength is 2.74 nm.

Answer 20

Ch. 1 - Prob. 1A.1AST Ch. 1 - Prob. 1A.1BST Ch. 1 - Prob. 1A.2AST Ch. 1 - Prob. 1A.2BST Ch. 1 - Prob. 1A.1E Ch. 1 - Prob. 1A.3E Ch. 1 - Prob. 1A.4E Ch. 1 - Prob. 1A.5E Ch. 1 - Prob. 1A.6E Ch. 1 - Prob. 1A.7E

Videos

Answer to Problem 1C.2E

Explanation of Solution

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).

Answer to Problem 1C.2E

Explanation of Solution

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Chapter 1 Solutions

Videos

Answer to Problem 1C.2E

Explanation of Solution

Interpretation: The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined. Concept Introduction: Refer to part (a).

Answer to Problem 1C.2E

Explanation of Solution

Want to see more full solutions like this?

Chapter 1 Solutions

Interpretation:

The wavelength for the transition for hydrogen atom from forth energy level to second energy level has to be determined.

Concept Introduction:

Refer to part (a).