Element having peaks at 75 .7 eV ( 7 .30 MJ ⋅ mol − 1 ) and 5 .38 eV ( 0 .519 MJ ⋅ mol − 1 ) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

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Answer 1

Question

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

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Done 11:14 ⚫ worksheets.beyondlabz.com 5 (a). Using the peak information you listed in the tables for both structures, assign each peak to that portion of the structure that produces the peak in the NMR spectrum. Draw this diagram on your own sheet of paper and attach the sketch of your drawing to this question. Question 6 5 (b). Using the peak information you listed in the tables for both structures, assign each peak to that portion of the structure that produces the peak in the NMR spectrum. Draw this diagram on your own sheet of paper and attach the sketch of your drawing to this question. Question 7 6. Are there any differences between the spectra you obtained in Beyond Labz and the predicted spectra? If so, what were the differences? <

2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled** Peak Chemical Shift (d) 5.7 1 Multiplicity multiplate .......... 5.04 double of doublet 2 4.98 double of doublet 3 4.05 doublet of quartet 4 5 LO 3.80 quartet 1.3 doublet 6 Peak Chemical Shift (d) Multiplicity

Answer 2

Question

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

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Answer 3

Question

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

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Answer 4

Question

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

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Answer 5

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Answer 6

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Answer 7

Chapter 1, Problem 1.11E

(a)

Interpretation Introduction

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Answer 9

(b)

Interpretation Introduction

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 1 - Prob. 1A.1AST Ch. 1 - Prob. 1A.1BST Ch. 1 - Prob. 1A.2AST Ch. 1 - Prob. 1A.2BST Ch. 1 - Prob. 1A.1E Ch. 1 - Prob. 1A.3E Ch. 1 - Prob. 1A.4E Ch. 1 - Prob. 1A.5E Ch. 1 - Prob. 1A.6E Ch. 1 - Prob. 1A.7E

Element having peaks at 75 .7 eV ( 7 .30 MJ ⋅ mol − 1 ) and 5 .38 eV ( 0 .519 MJ ⋅ mol − 1 ) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Solution Summary: The author explains the photoelectron spectroscopy of Lithium and its electron configuration by observing its peaks.

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

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Chapter 1 Solutions

Element having peaks at 75 .7 eV ( 7 .30 MJ ⋅ mol − 1 ) and 5 .38 eV ( 0 .519 MJ ⋅ mol − 1 ) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Solution Summary: The author explains the photoelectron spectroscopy of Lithium and its electron configuration by observing its peaks.

Interpretation: Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Interpretation: Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Want to see the full answer?

Chapter 1 Solutions

Interpretation:

Element having peaks at 75.7 eV(7.30 MJ⋅mol −1) and 5.38 eV(0.519 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.

Interpretation:

Element having peaks at 153 eV (14.8 MJ⋅mol −1) and 9.33 eV (0.90 MJ⋅mol −1) in the photoelectron spectra has to be identified and explained. Also, its electron configuration has to be written.