Chapter 1, Problem 1.98QP

Interpretation Introduction

Interpretation:

From the given data, it should be determined mass of DNA in grams and width of DNA in in meters.

Concept Introduction:

• DNA was estimated to have a mass of 308,859 amu.
• The average width of DNA double strand is approximately $\text{22}\stackrel{\text{o}}{\text{A}}$ to $\text{26}\stackrel{\text{o}}{\text{A}}$
• Conversion formula;

  $\begin{array}{l}\text{1}\text{amu}\text{=}\text{1}\text{.6605378}{\text{× 10}}^{\text{-24}}\text{g}\\ \stackrel{\text{ o}}{\text{1A}}\text{=}\text{1}\text{×}{\text{10}}^{\text{-10}}\text{m}\end{array}$