Chapter 1, Problem 1.87QP

Interpretation Introduction

Interpretation: It should be calculated for the total mass of the sodium chloride in kilogram and in tons.

Concept Introduction:

• Conversional formula;

$\begin{array}{l}\text{1}\text{ton}\text{=}\text{2000}\text{lb}\\ \text{1}\text{lb=453}\text{.6gm}\end{array}$

Volume is the ratio of mass to density and its SI unit is ${\text{m}}^{\text{3}}$

$Volume=\frac{Mass}{Density}$

Given:

The volume of the seawater is given.

The strategy is to use the given conversion factor to convert L.

$\text{seawater }\to \text{ g seawater }\to \text{ g NaCl}\text{.}$