Explanation Given Information: Steam temperature = 300 K and Steam Pressure = 200 kPa Write the ideal gas equation of state p V = n R T .. ( 1 ) Differentiate the equation (1), on both sides d ( p V ) = d ( n R T ) p d V + V d p = n R d T .. ( 2 ) As the specific heat is constant, the process can be considered as isothermal for which d T = 0 Substitute 0 for dT in equation (2), p d V + V d p = 0 p d V = − V d p p = ( d p − d V / V ) As the gas is ideal or the process is isothermal, bulk modulus will be equal to the pressure. β = p β = ( d p − d V / V ) Therefore, the formula for bulk modulus is β = ( d p − d V / V ) Obtain the specific volume at 300 ° C and 200 kPa from the properties of superheated water vapour

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ISBN: 9780073398273

Author: Frank M. White

Publisher: McGraw-Hill Education

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Chapter 1, Problem 1.76P

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By deriving a formula for the bulk modulus of an ideal gas, with constant specific heats, and calculate it for steam at 300 K and 200 kPa.

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Chapter 1, Problem 1.75P

Chapter 1, Problem 1.77P

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