To play Jeopardy, the answer is given. You must supply the question. Choose the best question for the following answer: Two recessive mutations in two different genes are united in one cell and the cell shows wild-type phenotype as both mutants are in the heterozygous state. What is suppressor? What is incomplete dominance? What is complementation? What is co-dominance?

To play Jeopardy, the answer is given. You must supply the question. Choose the best question for the following answer: Two recessive mutations in two different genes are united in one cell and the cell shows wild-type phenotype as both mutants are in the heterozygous state. What is suppressor? What is incomplete dominance? What is complementation? What is co-dominance?

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Description: To play Jeopardy, the answer is given. You must supply the question. Choose thebest question for the following answer:Two recessive mutations in two different genes are united in one cell and the cellshows wild-type phenotype as both mutants are in

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section: Chapter Questions

Problem 3CS: A couple was referred for genetic counseling because they wanted to know the chances of having a...

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To play Jeopardy, the answer is given. You must supply the question. Choose the best question for the following answer: Mutation in a second gene enhances the defects caused by a mutation in the first gene, leading to lethality. What is dominant negative? O What is suppressor? O What is recessive lethality? O What is synthetic lethal?
To play Jeopardy, the answer is given. You must supply the question. Choose the best question for the following answer: Mutant allele causing malfunction of the wild-type allele, giving rise to a dominant phenotype. What is codominance? What is incomplete dominance? O What is dominant negative? O What is haploinsufficiency?
The maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). Predict the outcome (normal vs. failed embryogenesis) inthe F1 and F2 generations of the cross described.
You have spent two decades studying a muscular dystrophy disorder. All previous pedigree data indicate this is an X-linked dominant trait, you notice that in one instance the trait skips one daughter coming from an effected father. If this disease is truly X-linked dominant, what is a likely explanation as to why it was not seen in this single female? O Only environmental conditions actually cause the disease O This disease may not be 100% penetrant for the disease O Skipping generations is common for X-linked dominant traits O The definition for X-linked dominant no longer means what it did when this disease was first discovered O This disease must not actually be X-linked dominant
The XG locus on the human X chromosome has twoalleles, XG+ and XG. The XG+ allele causes the presence of the Xg surface antigen on red blood cells,while the recessive XG allele does not allow antigento appear. The XG locus is 10 m.u. from the STSlocus. The STS+ allele produces normal activity ofthe enzyme steroid sulfatase, while the recessive STSallele results in the lack of steroid sulfatase activityand the disease ichthyosis (scaly skin). A man withichthyosis and no Xg antigen has a normal daughterwith Xg antigen. This daughter is expecting a child.a. If the child is a son, what is the probability he willlack Xg antigen and have ichthyosis?b. What is the probability that a son would have boththe antigen and ichthyosis?c. If the child is a son with ichthyosis, what is theprobability he will have Xg antigen?
Unaffected father Camier mother XY Unaffected Afected Carrier Unaffeded Unaffected daugkter U.S. National Lbrany of Mediche Carrier Affected son daughter son In humans, as well as in many other animals and some plants, the sex of the individual is determined by sex chromosomes. The sex chromosomes are one pair of non-homologous chromosomes: XX represents a female, while XY represents a male. When a gene for a specific trait is attached to the X or Y chromosome, we say it is sex-linked, and when it is attached to the X chromosome, we say it is X-linked. Alleles for these linked traits, such as hemophilia or color blindness, crosses, may be recessive or dominant. Hemophilia is an X-linked, recessive trait. The recessive allele for hemophilia is actually a mutated version of the normal alllele but it can still be passed on through generations. Imagine a female is a carrier for hemophilia; her genotype is Xx She is married to a man who does not have hemophilia. What conclusion is NOT valid…
of der(X) der(22) 22 der(X) 22 der(X) 22 First row is mother, second row is first daughter, third row is second daughter. Phenotype in first daughter was much more severe than second daughter. Give best explanation: O Inactivation in second daughter spread to the extra chromosome 22 segment O Having 45 chromosomes always gives a more severe phenotype than 46 chromosomes Pattern of inactivation in other tissues, including brain might differ, giving functional 22q monosomy O The presence of the third X in the second daughter decreases effect of genetic abnormality O irst daughter has a Turner-like syndrome, which explains severity --------- ---------- ---------- ------------ ---------. ------------- ------------ OO ix
. Chromosome 3 of corn carries three loci (b for plant-color booster, v for virescent, and lg for liguleless). A testcross of triple recessives with F1 plants heterozygous forthe three genes yields progeny having the followinggenotypes: 305 + v lg, 275 b + +, 128 b + lg, 112 + v +,74 + + lg, 66 b v +, 22 + + +, and 18 b v lg. Give the genesequence on the chromosome, the map distances between genes, and the coefficient of coincidence.
X-linked Recessive Inheritance A gene is described as X-linked when it occurs on the X chromosome and not the Y. Our convention is to indicate X-linkage by attaching the appropriate gene symbol as a superscript on the letter X. Commonly, the wild-type (+) allele is indicated with only a "+" to avoid having to type a superscript on a superscript. For example, a female that is heterozygous and carrying a recessive mutant allele is indicated as X+Xm. Note the convenience of the shorthand + for m+ in this situation. A mutant male has the genotype XmY. When working with X-linked inheritance, always include the X and Y chromosomes in the descriptions of genotypes, and include the sex (male or female) in the descriptions of the phenotypes (e.g., mutant male, wild-type female, etc.). Here are the genotypes and associated phenotypes for X-linked recessive inheritance: X+X+ Wild-type female X+Xm Wild-type female xmxm Mutant female X+Y xmy Wild-type male Mutant male
Cross C: Homozygote wild type flies (+/+) were crossed with white eye flies. The table shows the results for the F1 and F2 generations. White eye females Wild type females White eye males Wild type males 50 F1 phenotypes (observed) F2 phenotypes (observed) F2 - expected phenotypes 50 60 60 60 60 What does the F1 tell you about the trait? Is the gene on an autosome or sex chromosome? What was the genotypes of each parent, male and female? What are the genotypes of the F1 flies? The F1 were crossed with each other and the phenotypes found in F2 are shown in the table above. Are these results consistent with the F1 and your theory of inheritance of this gene? Do a X2 test to see if the observed numbers are consistent with your theory.
In 1952, an article in the British Medical Journalreported interesting differences in the behavior ofblood plasma obtained from several people who suffered from X-linked recessive hemophilia. Whenmixed together, the cell-free blood plasma from certain combinations of individuals could form clots inthe test tube. For example, the following table showswhether clots could form (+) or not (−) in variouscombinations of plasma from four people withhemophilia:1 and 1 − 2 and 3 +1 and 2 − 2 and 4 +1 and 3 + 3 and 3 −1 and 4 + 3 and 4 −2 and 2 − 4 and 4 −What do these data tell you about the inheritance ofhemophilia in these individuals? Do these data allowyou to exclude any models for the biochemical pathway governing blood clotting?
Incomplete dominance Codominance Dosage Dominant negative LOF ||| ||| An allele (or gene) that produces a new functional product. A mutation whose gene product produces a misshaped protein in the recessive condition and whose recessive allele will also cause the heterozygous protein product to misfold. Wild type or the phenotype of the typical form of a species as it occurs in nature. A mutation that results in a LOF. An allele (or gene) that no longer produces ✓ Open functional product.