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cance of color blindness in humans is due to a recessive gene located on the X chromosome X linked). Xe (color blind) r-blind boy is bom to a color-blind father (whose father was color blind) and a normal mother (whose father was also color blind. what are the genotypes of the parents? Use the letters Cand c for the color blind allele and X and Y for the sex chromosomes. Don't worry about writing the C/c next to the X chromoseme as a superscript - just write t the probability that the second child bom to that couple will be a color-blind daughter? Write your answers as a reduced fractioneg 1/16. Or write O if not possible uple has four children, what is the probability that the frst two children will be color-blind boys and the last two children will be girls with normal vision? Write your answers as a reduced fraction eg 1/16. Or write Oif not possible

cance of color blindness in humans is due to a recessive gene located on the X chromosome X linked). Xe (color blind) r-blind boy is bom to a color-blind father (whose father was color blind) and a normal mother (whose father was also color blind. what are the genotypes of the parents? Use the letters Cand c for the color blind allele and X and Y for the sex chromosomes. Don't worry about writing the C/c next to the X chromoseme as a superscript - just write t the probability that the second child bom to that couple will be a color-blind daughter? Write your answers as a reduced fractioneg 1/16. Or write O if not possible uple has four children, what is the probability that the frst two children will be color-blind boys and the last two children will be girls with normal vision? Write your answers as a reduced fraction eg 1/16. Or write Oif not possible

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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The inheritance of color blindness in humans is due to a recessive gene located on the X chromosome (X linked). X (normal) > Xc (color blind) 1. If a color-blind boy is born to a color-blind father (whose father was color blind) and a normal mother (whose father was also color blind), what are the genotypes of the parents? Use the letters C and c for the color blind allele and X and Y for the sex chromosomes. Don't worry about writing the C/c next to the X chromosome as a superscript - just write them like this - e.g. XCXC or XCY mother father 2. What is the probability that the second child born to that couple will be a color-blind daughter? Write your answers as a reduced fraction e.g. 1/16. Or write 0 if not possible probability 3. If this couple has four children, what is the probability that the first two children will be color-blind boys and the last two children will be girls with normal vision? Write your answers as a reduced fraction e.g. 1/16. Or write 0 if not possible probability
Transcribed Image Text:The inheritance of color blindness in humans is due to a recessive gene located on the X chromosome (X linked). X (normal) > Xc (color blind) 1. If a color-blind boy is born to a color-blind father (whose father was color blind) and a normal mother (whose father was also color blind), what are the genotypes of the parents? Use the letters C and c for the color blind allele and X and Y for the sex chromosomes. Don't worry about writing the C/c next to the X chromosome as a superscript - just write them like this - e.g. XCXC or XCY mother father 2. What is the probability that the second child born to that couple will be a color-blind daughter? Write your answers as a reduced fraction e.g. 1/16. Or write 0 if not possible probability 3. If this couple has four children, what is the probability that the first two children will be color-blind boys and the last two children will be girls with normal vision? Write your answers as a reduced fraction e.g. 1/16. Or write 0 if not possible probability
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