The miniature gene in Drosophila is located on the X-chromosome, It has two alleles; the mutant allele (m") encodes for wings that are reduced in size and is recessive to the wild-type (m*) allele that encodes for a normal size wing. What is the genotype of a true breeding, miniature male? Select one: Oa X/Y cross out Ob. X*/Y cross out Oc. m/m cross out Od. Xm+ X- cross out Oe. Xm/X cross out Of X/X cross out g. m /m* cross out h. m /m cross out

The miniature gene in Drosophila is located on the X-chromosome, It has two alleles; the mutant allele (m") encodes for wings that are reduced in size and is recessive to the wild-type (m) allele that encodes for a normal size wing. What is the genotype of a true breeding, miniature male? Select one: Oa X/Y cross out Ob. X/Y cross out Oc. m/m cross out Od. Xm+ X- cross out Oe. Xm/X cross out Of X/X cross out g. m /m* cross out h. m /m cross out

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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In Drosophila melanogaster, ebony body color is determined by the e allele. The e+ allele produces the wild-typehoney-colored body. In heterozygotes, the body is honey-colored except for a dark marking called the trident seen on the thorax. The e+ allele is thus considered to be incompletely dominant to the e allele.a. When female e+ e+ flies are crossed to male e+ e flies, what is the probability that progeny will have the tridentmarking? Animals with the marking mate among themselves. Of 100 progeny, how many would be expected to have a trident, how many would have ebony bodies, and how many would have honey-colored bodies?
Suppose a geneticist uses a three-point testcross to map three linked Drosophila recessive mutations called f, z, and n. Gene fis associated with abnormally fast movement, z is associated with a zigzag movement pattern, and n is associated with narrow wings. The geneticist first crosses homozygous narrow flies to homozygous fast, zigzag flies. Next, he testcrosses the F₁ progeny to fast, zigzag, narrow parents and obtains the results reported in the table. Based on the data, select the order of the three genes. fzn zfn nzf fnz znf nfz F₁ Testcross Progeny Phenotype narrow fast, zigzag zigzag fast, narrow fast zigzag, narrow fast, zigzag, narrow wild type Number 627 621 209 229 215 223 6 7
In Drosophila, an X-linked recessive mutation, (s) causes irregular wing margins. Give the genotypes, phenotypes and phenotypic ratio of the F1 and F2 offspring in the following crosses a. scalloped female crossed with a normal male b. scalloped male crossed with a homozygous normal female. Compare these results to those that would be obtained if the scalloped gene is autosomal.
In Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vg
Drosophila can have a yellow-brown body (wild-type [+]) or a black body [b] as a result of a mutation in the black gene (marked b). a mutation in the black gene (marked b). There is also a mutation in the purple gene (marked pr) which purple eyes (mutant phenotype [pr]). Flies with normal eyes are noted [+]. a/ Pure strains of male Drosophila [b] are crossed with female Drosophila [pr] (1st cross). The F1 progeny contains only wild-type Drosophila for the two [+, +] traits. both [+, +] traits. The reciprocal cross gives the same result. What information can you draw from this?
In Drosophila, females heterozygous for the recessive alleles c, d, and e were crossed to males homozygous recessive for these three mutant genes. The phenotypes of the resulting progeny were: cd+ 350 ++e 350 c + e 51 + d + 49 c + + 100 + d e 100 _________ _____ Total progeny 1000 How were the three pairs of alleles arranged in the heterozygous females? a. +d+/c+e B. cde/+++ C. +de/c++ D. cd+/++e
In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cM
In Drosophila, a gene controls body color producing either normal body color or the mutant form black body color (bl. A second gene controls wings. The flies either have normal wings or are wingless (wn). A cross is made between a homozygous wild type fly and fly with black body and wingless. A test cross was then performed. The following progeny was observed: Phenotype # Observed Wild Type 405 Normal, wingless 85 Black, normal 100 Black, wingless 410 A. List the genotypes of the original parents. B. List the genotypes of the testcross. C. Are these two genes linked? How do you know? Edit Format Table 12pt v Paragraph v BIUA
In a cross between Aa Bb XCDXCD and Aa Bb XCDY, the A gene controls earwax- where wet earwax is dominant to dry earwax. The B gene controls the ability to taste the bitter compound PTC. Tasting is dominant to non-tasting. A and B are found on different autosomal chromosomes. The C gene controls color vision- color vision is dominant to color blindness. And the D gene controls production of dystrophin, the gene disrupted in Duchene's Muscular Dystrophy. Individuals who have two copies of the recessive d allele or are hemizygous for the recessive d allele have muscular dystrophy. The parents have a child. What is the probability that child has wet earwax, can taste PTC, can see color, and has DMD? When the parents have 5 children. What is the probability that 4 of them are tasters, 1 of them is a non-taster, and all of them have wet earwax?
In Drosophila, the X-linked recessive mutation vermilion (v) causes bright red eyes, in contrast to the brick-red eyes of wild type. A separate autosomal recessive mutation, suppressor of vermilion (su-v), causes flies homozygous or hemizygous for v to have wildtype eyes. In the absence of vermilion alleles, su-v has no effect on eye color. Determine the F1 and F2 phenotypic ratios from a cross between a female with wild-type alleles at the vermilion locus, but who is homozygous for su-v, with a vermilion male who has wildtype alleles at the su-v locus
A homozygous fly with two recessive mutations causing purple body and short wings (ppss) is mated with a fly heterozygous for both mutations (p+p and s+s): "+" represents the wild-type allele. They have the following offspring: 26 Wild type (normal body, normal wings) 345 Purple body, normal wings 376 Normal body, short wings 13 Purple body, short wings What is the allele arrangement (haplotype) for the heterozygous parental fly? ("p" designates the mutant allele; "p+" designates the wild-type allele.)
Female Drosophila with cinnabar eye (cn) and vestigal wings (vg) were mated to males with roof wings (fr). The F1 were all wild type. When the F1 females were tested and crossed with male homozygous for all thrre traits, the following result were obtained. For this problem, rf, cn, vg is for roof wing / cinnabar eye / vestugal wing rf + cn + vg all wild typr(no definite phenotypr described.