In Drosophila, two genes w and s are X-linked and are 25 map units apal. heterozygous female fly with a genotype w* s*/ws (w* and s* are wild-type alleles) is crossed to a male wild-type fly. What percent of progeny will have only the wild- type alleles of the w and s genes? 50% 75% O 12.5% O 37.5% 25%

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter13: Genes, Chromosomes, And Human Genetics
Section: Chapter Questions
Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...
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**Drosophila Genetic Cross Problem**

In *Drosophila*, two genes \( w \) and \( s \) are X-linked and are 25 map units apart. A heterozygous female fly with a genotype \( w^+ s^+ / w s \) (\( w^+ \) and \( s^+ \) are wild-type alleles) is crossed to a male wild-type fly. What percent of progeny will have only the wild-type alleles of the \( w \) and \( s \) genes?

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### Answer Choices:

- \( \quad \) 50%
- \( \quad \) 75%
- \( \quad \) 12.5%
- \( \quad \) 37.5%
- \( \quad \) 25%

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### Diagram/Graph Description:

This question does not include any graphs or diagrams. It is a multiple-choice question related to genetics and inheritance patterns in *Drosophila* (fruit flies).

**Explanation:**

The question requires knowledge of genetic recombination and inheritance in X-linked genes. Map units (centimorgans) represent the probability of crossover events between two loci on a chromosome. Here, 25 map units indicate a 25% recombination frequency.

To find the required percentage of progeny with wild-type alleles ( \( w^+ s^+ \) ), consider recombination events and the resulting genotypes.

Please proceed with calculations or explanations related to genetic inheritance as needed to solve this problem.

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Transcribed Image Text:--- **Drosophila Genetic Cross Problem** In *Drosophila*, two genes \( w \) and \( s \) are X-linked and are 25 map units apart. A heterozygous female fly with a genotype \( w^+ s^+ / w s \) (\( w^+ \) and \( s^+ \) are wild-type alleles) is crossed to a male wild-type fly. What percent of progeny will have only the wild-type alleles of the \( w \) and \( s \) genes? --- ### Answer Choices: - \( \quad \) 50% - \( \quad \) 75% - \( \quad \) 12.5% - \( \quad \) 37.5% - \( \quad \) 25% --- ### Diagram/Graph Description: This question does not include any graphs or diagrams. It is a multiple-choice question related to genetics and inheritance patterns in *Drosophila* (fruit flies). **Explanation:** The question requires knowledge of genetic recombination and inheritance in X-linked genes. Map units (centimorgans) represent the probability of crossover events between two loci on a chromosome. Here, 25 map units indicate a 25% recombination frequency. To find the required percentage of progeny with wild-type alleles ( \( w^+ s^+ \) ), consider recombination events and the resulting genotypes. Please proceed with calculations or explanations related to genetic inheritance as needed to solve this problem. ---
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