Three recessive mutations in that affect eye colour, wing shape and body colourarew, m and b.The following numbers were obtained for testcross progeny in Drosophila.NumberPhenotype+ m +w + b+ + bw m+ m b21823616817895101w +++3w mb1(i)Determine the chromosomal composition of the heterozygous female parent.Construct a genetic map of the linkage group(s) these genes occupy. Show the orderand give the map distances between the genes.(ii)

In Drosophila , w , m , b are three mutations that impact on eye colour , shape of wing and body…

Three recessive mutations in that affect eye colour, wing shape and body colourarew, m and b. The following numbers were obtained for testcross progeny in Drosophila. Number 218 Phenotype + m + w + b + + b 236 168 178 w m + m b w + + + + 95 101 3 w m b 1 (i) Determine the chromosomal composition of the heterozygous female parent. Construct a genetic map of the linkage group(s) these genes occupy. Show the order and give the map distances between the genes. (ii)

Three recessive mutations in that affect eye colour, wing shape and body colourarew, m and b. The following numbers were obtained for testcross progeny in Drosophila. Number 218 Phenotype + m + w + b + + b 236 168 178 w m + m b w + + + + 95 101 3 w m b 1 (i) Determine the chromosomal composition of the heterozygous female parent. Construct a genetic map of the linkage group(s) these genes occupy. Show the order and give the map distances between the genes. (ii)

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

See similar textbooks

Related questions

Q: It is assumed that in Drosophila the following genotypes produce phenotypes. َA- B- = Red color A-…

A: Genetics may be a discipline of biology concerned with the study of genes, genetic diversity, and…

Q: h se g. +se+ + se g. ++g. h se + + + + h+g. h++ TOTAL Oh; 16.4 O se; 7.1 is the gene in the middle…

A: Genetic linkage is the tendency for genes located close to each other on the same chromosome to be…

Q: Considering the following chromosome which is represented as a series of genes on each arm separated…

A: The abrupt changes in DNA sequences is called as mutation it may be of many types for example point…

Q: THEME 3: In Drosophila recessive mutants called a, b, c, and d all have the same phenotype; namely,…

A: Wild type individuals result when the Plus sign is indicated and this Plus sign occurs when the two…

Q: The recessive alleles k (kidney-shaped eyes instead ofwild-type round), c (cardinal-colored eyes…

A: Inheritance or heredity is passing-on one trait from the parents to the progeny by either asexual or…

Q: You are given a Drosophila female that looks wild-type but is heterozygous for mutations in tan body…

A: Three-point cross: In genetics, the three-point cross is used to determine the distance between two…

Q: You design Drosophila crosses to provide recombinationdata for gene a, which is located on the…

A: The drosophila is commonly called fruit fly, and it is commonly used for the study of genetics. The…

Q: Drosophila females heterozygous for 3 recessive mutations a, b, and c were crossed to males…

A: The given cross involves Drosophila females that carry three recessive mutations (a, b, and c) in…

Q: 6). To investigate the genetic control of locomotive behavior in the diploid nematode,…

A: Complementation test is used to determine whether the mutation in two strains are in different gene.…

Q: Four homozygous recessive mutant lines of Drosophilamelanogaster (labeled 1 through 4) showed…

A: Introduction Heterozygous means that you have inherited various versions of a gene from each parent.…

Q: Given the following alleles that control the traits of Drosophila melanogaster: R = red eyes L =…

A: In this step the order of gene may be wrong, the correct order we will specify in further steps.…

Q: Vermilion eye color in Drosophila is sex-linked and recessive. What would be the phenotypes of male…

A: The sex-linked disease means the gene for the disease is present on X-chromosomes and is recessive…

Q: Because of non-disjunction in some stocks of Drosophila. melanogaster, about 1 in 65,000 egg cells…

A: Given:Non-disjunction in some stocks of Drosophila melanogaster results in about 1 in 65,000 egg…

Q: In Drosophila, a cross was made between females expressing thethree X-linked recessive traits, scute…

A: The genes that are in close proximity will have a very low chance of the occurrence of recombination…

Q: Two Drosophila flies that had normal (transparent, long) wings were mated. In the progeny, two new…

A: The question provides an interesting genetics scenario for Drosophila. Two transparent, long-winged…

Question

Three recessive mutations in that affect eye colour, wing shape and body colourarew, m and b.
The following numbers were obtained for testcross progeny in Drosophila.
Number
Phenotype
+ m +
w + b
+ + b
w m
+ m b
218
236
168
178
95
101
w +
+
+
3
w mb
1
(i)
Determine the chromosomal composition of the heterozygous female parent.
Construct a genetic map of the linkage group(s) these genes occupy. Show the order
and give the map distances between the genes.
(ii)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?
The gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show linkage. What does that mean in terms of their relative locations in the genome? What does it mean in terms of how the two traits are inherited with respect to each other?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
Mutations Can Uncouple chromosomal Sex from Phenotypic Sex Discuss whether the following individuals (1) have male or female gonads, (2) are phenotypically male or female (discuss Wolffian/Mllerian ducts and external genitalia), and (3) are sterile or fertile. a. XY, homozygous for a recessive mutation in the testosterone biosynthetic pathway, producing no testosterone b. XX, heterozygous for a dominant mutation in the testosterone biosynthetic pathway, which causes continuous production of testosterone c. XY, heterozygous for a recessive mutation in the MIH gene d. XY, homozygous fora recessive mutation in the SRY gene that abolishes function
A geneticist discovers that a girl with Down syndrome has a Robertsonian translocation involving chromosomes 14 and 21. If she has an older brother who is phenotypically normal, what are the chances that he is a translocation carrier?
Theodor Boveri predicted that malignancies would often be associated with chromosomal mutation. What lines of evidence substantiate this prediction?
a. If an individual who is homozygous for the mutation found in individual 2 and heterozygous for the mutation found in individual 4 marries an individual who is homozygous for the mutation found in individual 4 and heterozygous for the mutation found in individual 2, what will be the phenotype of their children? b. List the intermediate that would build up in each of the types of children who could not produce protein E.
The gene for flower position in pea plants exists as axial or terminal alleles. Given that axial is dominant to terminal, list all of the possible F1 and F2 genotypes and phenotypes from a cross involving parents that are homozygous for each trait. Express genotypes with conventional genetic abbreviations.
Equalizing the Expression of X Chromosome Genes in Males and Females Individuals with an XXY genotype are sterile males. If one X is inactivated early in embryogenesis, the genotype of the individual effectively becomes XY. Why will this individual not develop as a normal male?
Describe the chromosomal alterations and phenotype of cri du chat syndrome and Prader-Willi syndrome.