The kinetics of an enzyme were measured as a function of substrate concentration in the presence or absence of 104 M inhibitor. The following initial rate data were obtained: Substrate (So μM/L) 3 5 10 30 90 Velocity (Vo, umol/L-min) Without inhibition 10.4 14.5 22.5 33.8 40.5 With inhibition 2.1 2.9 4.5 6.8 8.1 Is this a competitive or noncompetitive inhibition? Evaluate KM, KI, and Vmax. (HINT: use linear regression to first estimate kinetic parameters for uninhibited and then for the inhibited)
The kinetics of an enzyme were measured as a function of substrate concentration in the presence or absence of 104 M inhibitor. The following initial rate data were obtained: Substrate (So μM/L) 3 5 10 30 90 Velocity (Vo, umol/L-min) Without inhibition 10.4 14.5 22.5 33.8 40.5 With inhibition 2.1 2.9 4.5 6.8 8.1 Is this a competitive or noncompetitive inhibition? Evaluate KM, KI, and Vmax. (HINT: use linear regression to first estimate kinetic parameters for uninhibited and then for the inhibited)
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The kinetics of an enzyme were measured as a function of substrate concentration in the
presence or absence of 10-4 M inhibitor. The following initial rate data were obtained:
Substrate (So µM/L)
3
5
Velocity (Vo, µmol/L-min)
Without inhibition
10
30
90
10.4
14.5
4.5
6.8
8.1
Is this a competitive or noncompetitive inhibition? Evaluate KM, KI, and Vmax. (HINT: use
linear regression to first estimate kinetic parameters for uninhibited and then for the
inhibited)
With inhibition
2.1
2.9
22.5
33.8
40.5
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Can you please give me a little more detail on finding Ki? Where did the values come from? 0.23, 0.15, etc
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