The following diagram illustrates a plot of the percent of O2 bound versus the concentration of O2, showing three possible curves labeled A, B, and C. Curve "B" represents the normal oxygen transport protein. The question posed is: "Suppose the local concentration of H+ increases. How might this be represented on the graph?"**Graph Explanation:**- The vertical axis represents the "Percent O2 bound."- The horizontal axis represents the concentration of O2.- Curve A: Steep initial slope, levels off at a lower percent.- Curve B: Moderate initial slope, levels off in the middle.- Curve C: Lower initial slope, levels off at a higher percent.**Question Options:**1. A shift from B to C2. H+ concentration has no effect (remains curve B)3. A shift from B to A

The association between the partial pressure of oxygen (PO2) and the percentage of hemoglobin…

Answered: The following plot (percent of O2 bound…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The following two reactions are coupled in the last step of glycolysis (catalyzed by the enzyme pyruvate kinase). РЕР + Н.О € Руr + Pi ADP + Pi → ATP + H2O AG° = -14.8 kcal/mol AG° = +7.3 kcal/mol D) The steady-state concentrations of ATP, ADP, and pyruvate in human erythrocytes are 2.24 mM, 0.25 mM, and 0.051 mM, respectively. What would be the concentration of PEP in these cells if the coupled reaction was at equilibrium?
a newly identified bacterium called Nomore biochem is unable to synthesize ubiquinone. A mobile electron carrier called CXC3 is used as a substitute. From the information provided in the table, calculate delta G' and Keq value at 298K for the redox reaction that occurs in the Nomore Biochem electron transport chain. (constants: R=8.3 J/degree x mol, F= 96.1 kJ/v x mol Half Reactions E' (V) ubiquinone + 2e- + 2H+--> Ubiquinol + H2 0.045 NAD+ + 2e- + 2H+ --> NADH + H+ -0.320 CXC3 + 2e- + 2H+ --> CXC3H2 -0.450 explain the impact that using CXC3 instead of ubiquinone will have on ATP production in the cell. How might the cell adapt to this situation?
Aconitase catalyzes the conversion of Citrate to Isocitrate in the TCA cycle. The standard free energy change (AG°) for this reaction is +6.7 kJ/mol. The observed free energy change (AG) for the reaction in pig heart mitochondria is +0.8 kJ/mol. The ratio of [isocitrate]/[citrate] in these mitochondria is: Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 10 b. 1 100 0.01 e f 0.33 0.10 h 0.25 i 2
Explain the processes of aerobic respiration in mitochondria of a cell and anaerobic respiration in yeast and muscle with the help of word equations.
Consider a series of experiments in which 32P-labeled inorganic phosphate were introduced to erythrocytes (red blood cells) undergoing glycolysis. Would you expect to see the labeled phosphate in any glycolytic intermediates? If so, which and at what relative concentrations?
If the enzyme lactase has a Vo of 0.111111111111 mM per minute when [S] = 1.0 mM, and a Vo of 0.20 mM per minute when [S] = 5.0 mM, what is its Km? 0.125 mM 0.25 mM 0.50 mM 1.25 mM 5.0 mM
The protein catalase is an enzyme that catalyzes the decomposition of hydrogen peroxide:2 H2O2 (aq) → 2 H2O (l) + O2 (g)and has a Michaelis-Menten constant of 25 × 10-3 mol·dm-3 and a turnover number of 4.0×107s-1.The total enzyme concentration is 0.016×10-6 mol·dm-3 and the initial substrate concentration is4.32×10-6 mol·dm-3 Calculate the maximum reaction rate (????) for this enzyme, and the initial rateof this reaction. Note that catalase has a single active site.
Intracellular concentrations in resting muscle are as follows: fructose- 6-phosphate, 1.0 mM; fructose-1,6-bisphosphate, 10 mM; AMP, 0.1 mM; ADP, 0.5 mM; ATP, 5 mM; and P, 10 mM. Is the phosphofructokinase reac- tion in muscle more or less exergonic than under standard conditions? By how much?
During vigorous exercise, a buffer system consisting of lactic acid and sodium lactate is produced in the muscle cells and released into circulation. (a) Calculate the concentration of lactate in the blood plasma (pH= 7.40) if the concentration of lactic acid in the blood is 1.50µM. {The pKa for lactic acid is 4.76}. (b) How is NADH recycled to NAD+when oxygen is a limiting factor during vigorous exercise? (c) Indicate the biochemical transformation that occurs in (b) above when aerobic conditions are restored during the resting state.
a) Assuming that ubiquinone is unavailable inside of the cell, calculate the AG and the Keq if electrons are transferred directly from complex I to complex III of the electron transport chain. In your answer include the net equation for this electron transfer. Constants: R= 8.3J/degree'mol, F= 96.1kJ/volt mol, T=298K ( Half Reaction EM ubiquinone + 2e + 2H' Ubiquinol + H2 NAD + 2e+ 2H'→ NADH + H 0.045 -0.320 1/202 + 2e +2H H,O Cytc (Fe") + +le + 1H"→ Cytc (Fe²) 0.816 0.254 b) In a single sentence explain whether or not this electron transfer is possible. /

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