(i) Calculate the physiological AG (not AG.) for the reaction: Phosphocreatine + ADP → creatine + ATP Given; Phosphocreatine + H;0- creatine + Pi ADP + Pi - ATP + H;0 AG.-43 kJ/mol AG.- +30.5 kl/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R = 8.315 JK mol')
(i) Calculate the physiological AG (not AG.) for the reaction: Phosphocreatine + ADP → creatine + ATP Given; Phosphocreatine + H;0- creatine + Pi ADP + Pi - ATP + H;0 AG.-43 kJ/mol AG.- +30.5 kl/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R = 8.315 JK mol')
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Transcribed Image Text:a) (1)
Calculate the physiological AG (not AG.) for the reaction:
Phosphocreatine + ADP - creatine + ATP
Given;
Phosphocreatine + H;0 - creatine + Pi
ADP + Pi → ATP + H;0
AG.' -43 kJ/mol
AG.- +30.5 kJ/mol
at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at
4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM.
(R = 8.315 JK-' mol-)
(ii)
Caleulate the free energy change at standard conditions for the following reaction:
Acetaldehyde + NADH + H* + Ethanol + NAD*
The half- reactions are:
Acetaldehyde + 2H + 2e +
Ethanol
E°- - 0.20V
NAD-+ 2H- + 2e ++
NADH + H-
E=-0.32V
(F= 96.485 kJ/V/mol)
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