Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 33 of the 39 subjects treated with echinacea developedrhinovirus infections. In a placebo group, 99 of the 113 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim thatechinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below.a. Test the claim using a hypothesis test.Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with aplacebo. What are the null and alternative hypotheses for the hypothesis test?O A. Ho: P1 2 P2H1: P1 # P2B. Ho: P1 + P2O C. Ho: P1 = P2H1: P1 = P2H: P1 # P2F. Ho: P1 = P2E. Ho: P1 sP2H4: P1 # P2D. Ho: P1 = P2H1: P1 > P2H4: P1 c. Based on the results, does echinacea appear to have any effect on the infection rate?A. Echinacea does appear to have a significant effect on the infection rate. There is evidence that it lowers the infection rate.B. Echinacea does appear to have a significant effect on the infection rate. There is evidence that it increases the infection rate.C. Echinacea does not appear to have a significant effect on the infection rate.O D. The results are inconclusive.

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Answered: Rhino viruses typically cause common…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- E
The Gallup Poll asked 1015 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 477 said they supported such a tax. Does the survey provide convincing evidence that less than 42% of U.S. adults favor an internet sales tax? Use the 0.05 level of significance. 1. STATE THE NULL AND ALTERNATIVE HYPOTHESIS: 2. T STATISTIC/ P VALUE 3.REJECT OR FAIL THE NULL HYPOTHESIS 4. IS THE CLAIM SUPPORTED AT THE 0.05 LEVEL OF SIGNIFICANCE?
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 40 of the 46 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 87 of the 104 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1≥p2 H1: p1≠p2 B. H0: p1=p2 H1: p1≠p2 C. H0: p1≠p2 H1: p1=p2 D. H0: p1=p2 H1: p1<p2 E. H0: p1=p2 H1: p1>p2 F. H0: p1≤p2 H1: p1≠ Identify the test statistic. Z = (Round to two decimal places as needed.) P-value= The P-value is (Less than/ greater than) the significance level of α=0.05,…
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PLEASE ONLY SELECT THE ANSWERS AS SHOWN FOR THE MULTIPLE CHOICE, SUCH AS OPTION 1, 2, ETC. In a study of 796 randomly selected medical malpractice lawsuits, it was found that 489 of them were dropped or dismissed. Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? A. H0: p>0.5 H1: p=0.5 B. H0: p<0.5 H1: p=0.5 C. H0: p≠0.5 H1: p=0.5 D. H0: p=0.5 H1: p>0.5 E. H0: p=0.5 H1: p<0.5 F. H0: p=0.5 H1: p≠0.5 What is the test statistic? Z=≠ (Round to two decimal places as needed.) What is the P-value? P-value= (Round to three decimal places as needed.) What is the conclusion about the null hypothesis? Reject the null hypothesis because the P-value is greater than the significance level, α. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. Fail to reject the null hypothesis because the…
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 44 of the 51 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 97 of the 110 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test?
Over the past few decades, public health officials have examined the link between weight concerns and teen girls' smoking. Researchers surveyed a group of 273 randomly selected teen girls living in Massachusetts (between 12 and 15 years old). After four years the girls were surveyed again. Sixty-three said they smoked to stay thin. Is there good evidence that more than thirty percent of the teen girls smoke to stay thin? Correctly identify the null and alternative hypotheses:
3
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