Find the value of the standard score, z, and determine whether the alternative hypothesis is supported or not supported at a 0.05 significance level. Ha: μ ≠ 18.7, n = 11, = 20.5, σ = 7
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Q: Test the claim that the proportion of men who own cats is significantly different than 60% at the…
A: The researcher claims that the proportion of men who own cats is significantly different than 60%.
Find the value of the standard score, z, and determine whether the alternative hypothesis is supported or not supported at a 0.05 significance level.
Ha: μ ≠ 18.7, n = 11, = 20.5, σ = 7
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- Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=2.6 for Hoμ=149 pounds and H₂: μ* 149 poundsIn the population of senior students at Shermer High School, the proportion who plan to attend college is 0.64. In a random sample of 100 students from this population, the proportion who plan to attend college is 0.75. We would call the value 0.64 a P-value. z-score. parameter statistic significance level.Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁ μM μF H₁:PM > PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 30% owned cats Based on a sample of 40 women, 45% owned cats The test statistic is: Ho: PM = PF H₁: PM μF (to 2 decimals) (to 2 decimals) Ho: PM = PF Ho: M = μF H₁:PM ‡ PF H₁: μM < MF
- Test the claim that the mean GPA of night students is significantly different than 3.2 at the 0.2 significance level.The null and alternative hypothesis would be: (multiple choice) H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=3.2H0:μ=3.2H1:μ>3.2H1:μ>3.2 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=3.2H0:μ=3.2H1:μ≠3.2H1:μ≠3.2 H0:μ=3.2H0:μ=3.2 H1:μ<3.2H1:μ<3.2 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: (multiple choice) left-tailed right-tailed two-tailed Based on a sample of 30 people, the sample mean GPA was 3.17 with a standard deviation of 0.07The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: (multiple choice) Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the mean GPA of night students is significantly different than 3.5 at the 0.1 significance level. The null and alternative hypothesis would be: Ho: µ = 3.5 Ho: µ = 3.5 Ho:p = 0.875 Ho:µ = 3.5 Ho:p= 0.875 Ho:p=0.875 H1: µ 3.5 H1:p# 0.875 H1:p > 0.875 The test is: two-tailed right-tailed left-tailed Based on a sample of 70 people, the sample mean GPA was 3.46 with a standard deviation of 0.04 The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesisTest the claim that the mean GPA of night students is smaller than 2.3 at the .005 significance level. The null and alternative hypothesis would be: Ho:p = 0.575 Ho:u = 2.3 Ho:4 = 2.3 Ho:p = 0.575 Ho:p = 0.575 Ho:4 = 2.3 H1:p > 0.575 H : u> 2.3 H1:4 < 2.3 H1:p < 0.575 H :p + 0.575 H1:4 # 2.3 The test is: right-tailed two-tailed left-tailed Based on a sample of 60 people, the sample mean GPA was 2.25 with a standard deviation of 0.04 The test statistic is: {to 2 decimals) The critical value is: {to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
- Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=3.5 for H₁: μ=124.5 kilograms and H₂: μ# 124.5 kilograms The P-value is (Round to four decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.05 significance level. O A. The P-value is more than the significance level. Do not reject Ho. The alternative hypothesis is not supported. OB. The P-value is more than the significance level. Reject Ho. The alternative hypothesis is supported. OC. The P-value is less than or equal to the significance level. Reject Ho. The alternative hypothesis is supported. O D. The P-value is less than or equal to the significance level. Do not reject Ho. The alternative hypothesis is not supported.Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF Incorrect The test is: left-tailed two-tailed right-tailed Incorrect Based on a sample of 20 men, 35% owned catsBased on a sample of 80 women, 40% owned catsThe test statistic is: Incorrect (to 2 decimals)The critical value is: Incorrect (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Incorrect Submit QuestionQuestion 6The weights of a sample of newborn calves are recorded in the table below: Male weight (kg) Female weight (kg) 36.8 37.2 12.6 39.1 38.2 41.7 31.9 46.8 37.5 43.0 45.7 42.2 31.3 A hypothesis test at a 5% level of significance is conducted to see whether the mean weight of male calves, is the same as the mean weight ir of female calves. a State the null and alternative hypotheses. b Assuming the weights of both male and female calves are normally distributed with the same standard deviation, calculate the p-value for this test. c State, with a reason, whether the null hypothesis should be uccepted.
- Test the claim that the proportion of men who own cats is significantly different than 20% at the 0.02 significance level. The null and alternative hypothesis would be: Ho:µ = 0.2 Ho:H = 0.2 Ho:p= 0.2 Ho:µ = 0.2 Ho:p= 0.2 Ho:p= 0.2 H1: µ > 0.2 H1:470.2 H1:p7 0.2 H1:µ 0.2 The test is: left-tailed right-tailed two-tailed Based on a sample of 4 people, 25% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis Check AnswerTest the claim that the mean GPA of night students is significantly different than 2.7 at the 0.04 significance level.The null and alternative hypotheses would be: H0:μ=2.7H0:μ=2.7H1:μ≠2.7H1:μ≠2.7 H0:p=0.675H0:p=0.675H1:p>0.675H1:p>0.675 H0:p=0.675H0:p=0.675H1:p<0.675H1:p<0.675 H0:μ=2.7H0:μ=2.7H1:μ>2.7H1:μ>2.7 H0:p=0.675H0:p=0.675H1:p≠0.675H1:p≠0.675 H0:μ=2.7H0:μ=2.7H1:μ<2.7H1:μ<2.7 The test is: left-tailed two-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.66 with a standard deviation of 0.16The p-value is: (to 3 decimals)The positive significance level is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.05 significance level. The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: left-tailed right-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 40 women, 30% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
