Test the claim that the mean GPA of night students is significantly different than 2.1 at the 0.01significance level.The null and alternative hypothesis would be:Ho:p < 0.525 Họ:µ < 2.1 Họ:p = 0.525 Ho:µ > 2.1 Ho:µ = 2.1 Ho:p 2 0.525Ні:р > 0.525 Hi:д > 2.1 Hi:р#0.525 Hi:д < 2.1 Н::д + 2.1 H:p<0.525%3DThe test is:right-tailed two-tailed left-tailedBased on a sample of 65 people, the sample mean GPA was 2.07 with a standard deviation of 0.03The p-value is:(to 2 decimals)Based on this we:O Reject the null hypothesisO Fail to reject the null hypothesis

Given Population mean μ=2.1, level of significance ɑ=0.01

Answered: Test the claim that the mean GPA of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Test the claim that the proportion of men who own cats is larger than 70% at the .025 significance level.The null and alternative hypothesis would be: H0:μ=0.7H0:μ=0.7H1:μ≠0.7H1:μ≠0.7 H0:p=0.7H0:p=0.7H1:p>0.7H1:p>0.7 H0:p=0.7H0:p=0.7H1:p<0.7H1:p<0.7 H0:p=0.7H0:p=0.7H1:p≠0.7H1:p≠0.7 H0:μ=0.7H0:μ=0.7H1:μ>0.7H1:μ>0.7 H0:μ=0.7H0:μ=0.7H1:μ<0.7H1:μ<0.7 The test is: right-tailed two-tailed left-tailed Based on a sample of 100 people, 79% owned catsThe test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
You wish to test the following claim (HaHa) at a significance level of α=0.02α=0.02.      Ho:μ1=μ2Ho:μ1=μ2      Ha:μ1<μ2Ha:μ1<μ2You believe both populations are normally distributed, but you do not know the standard deviations for either. However, you also have no reason to believe the variances of the two populations are not equal. You obtain the following two samples of data. Sample #1 Sample #2 61.5 80.2 53.7 61.5 73.7 82.6 76.7 96.3 50 60.5 74.9 85.8 88.7 90.3 63.4 93.5 71.1 94 83 66.9 83 72.9 74.5 85.8 71.5 99.7 94.9 92.4 86 93.7 78.8 99.7 91.2 96 82.7 88.6 91 89.8 90 92.7 98.3 98 What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater…
ou wish to test the following claim (Ha) at a significance level of α=0.005.      Ho:μ1=μ2       Ha:μ1≠μ2You believe both populations are normally distributed, but you do not know the standard deviations for either, and you have no reason to believe the variances of the two populations are equal. You obtain a sample of size n1=18 with a mean of M1=81.6 and a standard deviation of SD1=8.2 from the first population. You obtain a sample of size n2=23 with a mean of M2=88.9 and a standard deviation of SD2=5.8 from the second population. What is the test statistic for this sample? (Report answer accurate to two decimal places.) test statistic =
In the past, the mean lifetime for a certain type of flashlight battery has been 9.5 hours. The manufacturer has introduced a change in the production method and wants to perform a significance test to determine whether the mean lifetime has increased as a result. The hypotheses are: null: μ = 9.5 hours alternative: u 9.5 hours Suppose that the results of a significance test result in a rejection of the null hypothesis. If we later find out that the true population running time was actually equal to 10.5, what error has been committed? Type I and Type II error Type II error no error Type I error
In 1990, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephone company wants to perform a significance test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. The hypotheses are: H0: μ = 9.4 minutes HA: μ ≠ 9.4 minutesSuppose that the results of the sample lead to non-rejection of the null hypothesis. Classify that conclusion as a Type I error, a Type II error, or a correct decision, if in fact the mean duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. Choose the best asnwer below: A. Neither B. Type I error C. Type II error D.No error
Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.10 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is: right-tailed left-tailed two-tailed The sample consisted of 55 night students, with a sample mean GPA of 2.32 and a standard deviation of 0.05, and 55 day students, with a sample mean GPA of 2.37 and a standard deviation of 0.02.The test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: two-tailed right-tailed left-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 40 women, 40% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Check AnswerQuestion 14
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: left-tailed two-tailed right-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 40 women, 55% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 300 people, 74% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than 30% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p = 0.3 Ho:p = 0.3 Ho:u = 0.3 Ho:µ = 0.3 Ho:p = 0.3 Ho:u = 0.3 H1:p # 0.3 H1:p > 0.3 H1:4 > 0.3 H1:µ < 0.3 H1:p < 0.3 H1:u + 0.3 The test is: left-tailed two-tailed right-tailed Based on a sample of 50 people, 22% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis Reject the null hypothesis

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