The null and alternative hypothesis would be: Ho:p = 0.8 Ho: 4 3.2 Ho:p < 0.8 Ho:p 2 0.8 Ho: 4 = 3.2 Ho:u < 3.2 H1:p # 0.8 H1:4 < 3.2 H1:p > 0.8 H1:p < 0.8 H1:u # 3.2 H1: 4 > 3.2 The test is: left-tailed right-tailed two-tailed Based on a sample of 65 people, the sample mean GPA was 3.24 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
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- Write the null and alternative hypothesis. Are Americans getting fatter? Researchers interested in this question take a random sample of 500 people and record an average weight of 190 pounds. Ten years ago, the average weight was 185 pounds. OA Ho: H= 190 HA: H> 190 О в. Но: и 185 HAiH> 185 OC. Ho: u= 190 HA:u< 190 O D. Ho: u= 185 HA: H< 185 OE. Ho:H= 185 HA u# 185Consumers Energy states that the average electric bill across the state is $60.07. You want to test the claim that the average bill amount is actually greater than $60.07. What are the appropriate hypotheses for this test? Question 12 options: 1) HO: μ ≥ 60.07HA: μ < 60.07 2) HO: μ = 60.07HA: μ ≠ 60.07 3) HO: μ > 60.07HA: μ ≤ 60.07 4) HO: μ ≤ 60.07HA: μ > 60.07 5) HO: μ < 60.07HA: μ ≥ 60.07Which of the following below could be the null hypothesis ? ( look at the image )
- 1. The results of a hypothesis test with an independent-measures t statistic are reported as follows: t(22) 2.48, p < .05. Which of the following is an accurate description of the study and the result? a. The study used a total of 24 participants and the null hypothesis was not rejected. b. The study used a total of 22 participants and the null hypothesis was rejected. (incorrect answer) c. The study used a total of 24 participants and the null hypothesis was rejected. d. The study used a total of 22 participants and the null hypothesis was not rejected.State the null and alternate hypotheses OM 16.4 R ₁-16.4 OM: 16.4 ; M₁: -16.4 OMR-16.4; H₁ > 16.4R 0.250 O 0.100 < P-value < 0.250 O 0.050 P-value 0.100 O 0.010 P-value 0.050 OP-value < 0.010 Sketch the sampling distribution and show the area corresponding to the P-value. 0-3 01 -2 -10 0-3 o (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level a? At the 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. At the 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant. At the 0.01 level, we fail to reject the nut hypothesis and conclude the data are statistically significant. At the 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant -2 -1 . 1 TROTES (e) Interpret your conclusion in the context of the application O There is sufficient evidence at the 0.01…A random group of customers at a fast food chain were asked whether they preferred hamburgers, chicken sandwiches, or fish sandwiches. The restaurant's marketing department claims that 45% of customers prefer hamburgers, 45% of the customers prefer chicken sandwiches, and 10% of the customers prefer fish sandwiches. Is there evidence to reject this hypothesis at = 0.05? Plans Hamburgers Chicken Fish Number of students 34 18 8 Group of answer choices A. There is evidence to reject the claim that the customers' preferences are distributed as claimed because the test value 17.2> 5.481 B. There is not evidence to conclude the claim that the customers' preferences are distributed as claimed because the test value 5.481 < 7.815 C. There is not evidence to reject the claim that the customers' preferences are distributed as claimed because the test value 5.481 < 5.991 D. There is evidence to conclude the claim that the customers' preferences are…
- 1. What is the hypothesis for each problem below? When selecting answers: p0 is written "p0", μ0 is written "Mu0", ≠ is written "not =" A company claimed that more than 80% of their employees are satisfied with their employment. Null: H0: [p0 or Mu0] = .8 Alternate: Ha: [p0 or Mu0] [<, not =, or >] .8 A company claims that the average weight for the delivery of their product is less than 2 weeks. Null: H0: [p0 or Mu0] = 2 Alternate: Ha: [p0 or Mu0] [<, not =, or >] 2 A company claims that the average number of years an employee has worked for them is 15 years Null: H0: [p0 or Mu0] = 2 Alternate: Ha: [p0 or Mu0] [<, not =, or >] 2You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies:HoHo : pA=0.1pA=0.1; pB=0.5pB=0.5; pC=0.3pC=0.3; pD=0.1pD=0.1Complete the table. Category ObservedFrequency ExpectedFrequency SquaredResidual A 16 B 39 C 28 D 14 What is the chi-square test-statistic for this data?χ2= Report all answers accurate to three decimal places.You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies:HoHo : pA=0.3pA=0.3; pB=0.3pB=0.3; pC=0.2pC=0.2; pD=0.2 Complete the table. Category ObservedFrequency ExpectedFrequency SquaredResidual A 35 B 25 C 15 D 25
- (a) Express the null hypothesis and the alternative hypothesis in symbolic form for the following claim. A manager claims that the average lunch break is more than 0.4 hours long. O Ho: p = 0.4 vs. H: p 0.4 H;: µ # 0.4 O Ho: H = 0.4 vs. H: µ > 0.4 O Ho: p = 0.4 Hi:p # 0.4 Vs. (b) State the indicated conclusion in nontechnical terms, being sure to address the original claim. An entomologist writes an article in a scientific journal claiming that at most 1.48% of male fireflies are unable to produce light due to a genetic mutation. A hypothesis test of the claim has been conducted, and the decision from that test is to fail to reject Ho. O There is not sufficient evidence to warrant rejection of the claim that the true proportion is at most 1.48%. O There is sufficient evidence to warrant rejection of the claim that the true proportion is at most 1.48%. OThere is not sufficient evidence to support the claim that the true proportion is at most 1.48%. O There is sufficient evidence to…If your null and alternative hypothesis are:H0:p=0.78 H1:p<0.78Then the test is: two tailed right tailed left tailed20. Which of the following is a null hypothesis? a. Pregnant women who drink cranberry juice will have lower urine bacterial counts than those who do not drink cranberry juice. b. The urine bacterial count of pregnant women who drink cranberry juice will be lower or equal to that of pregnant women who do not drink the juice. c. There will be a difference between ingestion of cranberry juice and among pregnant women who do and do not have high urine bacterial counts.