Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 34 of the 41 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 88 of the 102 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. (a) Test a claim using a hypothesis test. Ho:P1 = P2 H1: Answer : A for Pi < P2; answer: B for p1 > P2 ; or answer: C for p1 # P2 Identify the test statistic. z = (Round to two decimal places as needed.) Identify the P-value. p-value Conclusion: since p-value is the significance level of a = 0.01, so ( fail to reject or reject) (b) Test claim by constructing an appropriate confidence interval < P1 - P2 < (Round to three decimal places.)

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Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 34 of the 41 subjects treated with echinacea developed rhinovirus infections. In a
placebo group, 88 of the 102 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus
infections.
(a) Test a claim using a hypothesis test.
Ho:P1 = P2
H1:
Answer : A for Pi < P2; answer: B for p1 > P2 ; or answer: C for p1 # P2
Identify the test statistic.
z =
(Round to two decimal places as needed.)
Identify the P-value.
p-value
Conclusion: since p-value is
the significance level of a = 0.01, so
( fail to reject or reject)
(b) Test claim by constructing an appropriate confidence interval
< P1 - P2 <
(Round to three decimal places.)
Transcribed Image Text:Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 34 of the 41 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 88 of the 102 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. (a) Test a claim using a hypothesis test. Ho:P1 = P2 H1: Answer : A for Pi < P2; answer: B for p1 > P2 ; or answer: C for p1 # P2 Identify the test statistic. z = (Round to two decimal places as needed.) Identify the P-value. p-value Conclusion: since p-value is the significance level of a = 0.01, so ( fail to reject or reject) (b) Test claim by constructing an appropriate confidence interval < P1 - P2 < (Round to three decimal places.)
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