According to the Center for Disease Control (CDC) during the 2018-2019 season the percent of Americans 18 and older who had a flu shot was 45.3%. We did a random sample of 500 Americans and found that 200 out of the 500 had a flu shot. Is there enough evidence at the 5% level that 45.3% or less of Americans 18 or older had a flu shot?What is given and which test will your perform?:a) u = 0.453, x-bar = 200/500 = 0.40, n = 500, T test with less thanb) p = 200/500 = 0.40, p-hat = 0.453, n = 500, 1 prop z test with less thanc) p = 0.453, p-hat = 200/500 = 0.40, n = 500, 1 prop z test with less thand) p = 0.453, p-hat = 200/500 = 0.40, n = 500, 2 prop z test with less than According to the Center for Disease Control (CDC) during the 2018-2019 season the percent of Americans 18 and older who had a flu shot was45.3%. We did a random sample of 500 Americans and found that 200 out of the 500 had a flu shot. Is there enough evidence at the 5% level that45.3% or less of Americans 18 or older had a flu shot?What is given and which test will your perform?:O u = 0.453, x-bar = 200/500 = 0.40, n = 500, T test with less thanOp = 200/500 = 0.40, p-hat = 0.453, n = 500, 1 prop z test with less thanO p = 0.453, p-hat = 200/500 = 0.40, n = 500, 1 prop z test with less thanOp = 0.453, p-hat = 200/500 = 0.40, n = 500, 2 prop z test with less than

Given that p=45.3% , n=500 , X=200

Answered: According to the Center for Disease…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to the Center for Disease Control (CDC) during the 2018-2019 season the percent of Americans 18 and older who had a flu shot was 45.3%. We did a random sample of 500 Americans and found that 200 out of the 500 had a flu shot. Is there enough evidence at the 5% level that 45.3% or less of Americans 18 or older had a flu shot?

What is given and which test will your perform?:

a) u = 0.453, x-bar = 200/500 = 0.40, n = 500, T test with less than

b) p = 200/500 = 0.40, p-hat = 0.453, n = 500, 1 prop z test with less than

c) p = 0.453, p-hat = 200/500 = 0.40, n = 500, 1 prop z test with less than

d) p = 0.453, p-hat = 200/500 = 0.40, n = 500, 2 prop z test with less than