According to a survey conducted by the Association for Dressings and Sauces, 20% of Americanadults eat salad once a week. A nutritionist suspects that this percentage is not accurate. Sheconducts a survey of 579 American adults and finds that 104 of them eat salad once a week. Use a0.10 significance level to test the claim that the proportion of American adults who eat salad once aweek is equal to 20%.Claim: p = 0.2v which corresponds to H0: p = 0.2Opposite: p 0.2v which corresponds to H1 p + 0.2The test is: right-tailedThe test statistic is: z=(to 2 decimals)The Critical Value is: z=Based on this we: Fail to reject the null hypothesis vConclusion: There does notproportion of American adults who eat salad once a week is equal to 20%.v appear to be enough evidence to support the claim that theSubmit Questionthing近

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According to a survey conducted by the Association for Dressings and Sauces, 20% of American adults eat salad once a week. A nutritionist suspects that this percentage is not accurate. She conducts a survey of 579 American adults and finds that 104 of them eat salad once a week. Use a 0.10 significance level to test the claim that the proportion of American adults who eat salad once a week is equal to 20%. Claim: p = 0.2 which corresponds to H0: p = 0.2 Opposite: p 0.2 which corresponds to H1: p 0.2 The test is: right-tailed The test statistic is: %= (to 2 decimals) The Critical Value is: z= Based on this we: Fail to reject the null hypothesis v Conclusion: There does not appear to be enough evidence to support the claim that the proportion of American adults who eat salad once a week is equal to 20%. Submit Question

According to a survey conducted by the Association for Dressings and Sauces, 20% of American adults eat salad once a week. A nutritionist suspects that this percentage is not accurate. She conducts a survey of 579 American adults and finds that 104 of them eat salad once a week. Use a 0.10 significance level to test the claim that the proportion of American adults who eat salad once a week is equal to 20%. Claim: p = 0.2 which corresponds to H0: p = 0.2 Opposite: p 0.2 which corresponds to H1: p 0.2 The test is: right-tailed The test statistic is: %= (to 2 decimals) The Critical Value is: z= Based on this we: Fail to reject the null hypothesis v Conclusion: There does not appear to be enough evidence to support the claim that the proportion of American adults who eat salad once a week is equal to 20%. Submit Question

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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