Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported?z=2.6 for Ho: μ=149 pounds and H₂: μ* 149 pounds

The null hypothesis (H0) is that the population mean (μ) is 149 pounds. The alternative hypothesis…

Answered: Find the P-value that corresponds to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF Incorrect The test is: left-tailed two-tailed right-tailed Incorrect Based on a sample of 20 men, 35% owned catsBased on a sample of 80 women, 40% owned catsThe test statistic is: Incorrect (to 2 decimals)The critical value is: Incorrect (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Incorrect Submit QuestionQuestion 6
Test the claim that the mean GPA of night students is significantly different than 2.7 at the 0.04 significance level.The null and alternative hypotheses would be: H0:μ=2.7H0:μ=2.7H1:μ≠2.7H1:μ≠2.7 H0:p=0.675H0:p=0.675H1:p>0.675H1:p>0.675 H0:p=0.675H0:p=0.675H1:p<0.675H1:p<0.675 H0:μ=2.7H0:μ=2.7H1:μ>2.7H1:μ>2.7 H0:p=0.675H0:p=0.675H1:p≠0.675H1:p≠0.675 H0:μ=2.7H0:μ=2.7H1:μ<2.7H1:μ<2.7 The test is: left-tailed two-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.66 with a standard deviation of 0.16The p-value is: (to 3 decimals)The positive significance level is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
Test the claim that the mean GPA of night students is smaller than 2.8 at the .05 significance level. The null and alternative hypothesis would be: = 2.8 Ho:p= 0.7 Ho:μ = 2.8 : Ho p= 0.7 Ho:μ = 2.8 Ho: p = 0.7 Ho:μ = H₁:p 2.8 H₁:p 0.7 H₁:μ 0.7 H₁:μ ‡ 2.8 The test is: right-tailed two-tailed left-tailed Based on a sample of 50 people, the sample mean GPA was 2.75 with a standard deviation of 0.02 The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z=1.95. A. 0.9744; fail to reject the null hypothesis B. 0.0512; fail to reject the null hypothesis C. 0.0512; reject the null hypothesis D. 0.0256; reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than 2.2 at the 0.01 significance level. The null and alternative hypothesis would be: Ho: p = 0.55 H₁: p > 0.55 Ho : μ = 2.2 H₁ : µ 2.2 Ho:|=2.2 H₁: μ2.2 O Ho: p = 0.55 H₁: p0.55 O Ho: p = 0.55 H₁: p < 0.55 Based on a sample of 80 people, the sample mean GPA was 2.22 with a standard deviation of 0.06 The test statistic is decimals) The positive critical value is Based on this we (to 3 decimals) reject the null hypothesis fail to reject the null hypothesis (to 3
Test the claim that the mean GPA of night students is larger than 2.1 at the 0.01 significance level. The null and alternative hypotheses would be: 0.525 Ho: u = 2.1 Ho: µ = 2.1 Ho:µ = 2.1 Ho:p 0.525 Ho:p 0.525 H:p> 0.525 H1:p+ 2.1 H:µ > 2.1 H:µ < 2.1 H1:p< 0.525 H :p + 0.525 The test is: left-tailed two-tailed right-tailed Based on a sample of 38 people, the sample mean GPA was 2.11 with a standard deviation of 0.2 The p-value is: (to 3 decimals) The significance level is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: Message instructor Submit Question N D arch
State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.
Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?
If the p-value of a hypothesis test is equal to 0.035, then the null hypothesis will be rejected for which cases? SELECT ALL THAT APPLY. a. for a significance level of 0.01 b. for a significance level of 0.10 c. for a significance level of 0.05 d. for a significance level of 0.02
Test the daim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.05 significance level. The null and alternative hypothesis would be: Ho:PN = PD Ho:HN > Hp Ho:PN > PD Ho:HN = HD Ho:HN µp Ha:PN > PD The test is: right-tailed left-tailed two-tailed The sample consisted of 16 night students, with a sample mean GPA of 3.28 and a standard deviation of 0.02, and 14 day students, with a sample mean GPA of 3.3 and a standard deviation of 0.03. test statistic = [three decimal accuracy] p-value = [three decimal accuracy] Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 2.5 at the 0.005 significance level.The null and alternative hypothesis would be: H0:p=0.625H0:p=0.625H1:p≠0.625H1:p≠0.625 H0:μ=2.5H0:μ=2.5H1:μ≠2.5H1:μ≠2.5 H0:p≤0.625H0:p≤0.625H1:p>0.625H1:p>0.625 H0:μ≤2.5H0:μ≤2.5H1:μ>2.5H1:μ>2.5 H0:p≥0.625H0:p≥0.625H1:p<0.625H1:p<0.625 H0:μ≥2.5H0:μ≥2.5H1:μ<2.5H1:μ<2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 75 people, the sample mean GPA was 2.51 with a standard deviation of 0.05The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

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Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=2.6 for Ho: μ=149 pounds and H₂: μ* 149 pounds