! Required information An abrasive cutoff wheel has a diameter of 5 in, is 1/16 in thick, and has a 3/4-in bore. The wheel weighs 4.80 oz and runs at 11,700 rev/min. The wheel material is isotropic, with a Poisson's ratio of 0.20, and has an ultimate strength of 12 kpsi. Choose the correct equation from the following options: Multiple Choice о σmax= (314) (4r2 — r²) - о σmax = p² (3+) (4r² + r²) 16 σmax = (314) (4r² + r²) σmax = (314) (4² - r²)
! Required information An abrasive cutoff wheel has a diameter of 5 in, is 1/16 in thick, and has a 3/4-in bore. The wheel weighs 4.80 oz and runs at 11,700 rev/min. The wheel material is isotropic, with a Poisson's ratio of 0.20, and has an ultimate strength of 12 kpsi. Choose the correct equation from the following options: Multiple Choice о σmax= (314) (4r2 — r²) - о σmax = p² (3+) (4r² + r²) 16 σmax = (314) (4r² + r²) σmax = (314) (4² - r²)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Required information
An abrasive cutoff wheel has a diameter of 5 in, is 1/16 in thick, and has a 3/4-in bore. The wheel weighs 4.80 oz and
runs at 11,700 rev/min. The wheel material is isotropic, with a Poisson's ratio of 0.20, and has an ultimate strength of 12
kpsi.
Choose the correct equation from the following options:
Multiple Choice
о
σmax=
(314) (4r2 — r²)
-
о
σmax = p² (3+) (4r² + r²)
16
σmax =
(314) (4r² + r²)
σmax =
(314) (4² - r²)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1467f162-7185-45ab-925a-2589d3c8cce7%2F9802aaa1-349b-4b79-8e26-3b11cc42f26d%2Fxbg96hd_processed.png&w=3840&q=75)
Transcribed Image Text:!
Required information
An abrasive cutoff wheel has a diameter of 5 in, is 1/16 in thick, and has a 3/4-in bore. The wheel weighs 4.80 oz and
runs at 11,700 rev/min. The wheel material is isotropic, with a Poisson's ratio of 0.20, and has an ultimate strength of 12
kpsi.
Choose the correct equation from the following options:
Multiple Choice
о
σmax=
(314) (4r2 — r²)
-
о
σmax = p² (3+) (4r² + r²)
16
σmax =
(314) (4r² + r²)
σmax =
(314) (4² - r²)
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