The second moment of area about z-axis of the cross section, Izz ( Units: mm4) can be calculated as Select one: O 1. 2.081 x 107 ○ 2. 2.281x 107 ○ 3. 2.201 x 107 ○ 4. 1.348x 107 ○ 5. 1.466 x107 ○ 6. 1.966x107 O 7. 1.833 x 107 O 8. 1.109x 107
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- Build the following part. Report the volume in mm^3. Assume all dimensions are in mm. A = 44 B = 78 40 20 10 Ø10 40 20 B 15 10 15 R20 30 10 T 20-Three forces intersect at point (1, 1, 1). Their magnitude and respective second point of incidence are as follows: 450 lbs (4, -3, 7), 600lbs (-1, 5, -4), 300lbs (-3, 6, -2) 1. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 2. Compute the direction cosine on the y-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 3. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513Find the first moment of area, why don’t you include the middle portion in the calculation?
- Q8A guy who works out at your gym found out that you are an engineer and has hired you do an analysis comparing two versions of a similar exercise: lateral raises. He wants to compare using dumbbells (as in Fig 1) versus using a cable machine (as in Fig 2). Develop an equation for each case for the moment about the shoulder as a function of angle. (0 to 90 horizontally) You will use your own dimensions for this analysis. You will need to measure: Arm length from shoulder joint to palm of your hand Height from shoulder joint to the ground Wingspan with arms held horizontally (palm-to-palm) You can use any measurements for the dimensions, just need the equations and FBD Fig 1: Dumbbell Lateral Raises Fig 2: Cable Lateral Raises1 0 Calculate the total volume of the cylindrical component below (not to scale): L1 D1- D1 = 1.12 cm D2 = 0.71 cm D3 = 1.58 cm L1 = 18.68 cm L2 = 15.36 cm L3=13.77 cm L4 = 9.77 cm Answer: Check L2 L3 L4 D2- What is the volume of the cylindrical component? (State your answer in S.I. units (m³), accurate to 3 significant figures) D3
- ENTER YOUR ANSWER THE WAY I SPECIFY HERE IN ADDITION TO DOING IT ON SCRATCH PAPER Copyright © McGraw-Hill Education. Permission required for reproduction or display. -3.6 m A 2400 N 2.7 m D 2.7 m F E -4.8 m a. Determine the vertical component Cy and its direction at C (use "up" or "down"); enter your answer as a whole number. b. Determine the vertical component Ay and its direction at A (use "up" or "down"); enter your answer as a whole number. Example If Cy=300.5 N in the positive direction and if Ay=200.3 N in the negative direction, enter 301up;200down in that order. B CCalculate the Resultant Condition of the PIN in the drawing below: 1.000 O 1.060 .982 .995 O .008 C 2.000 Ø.995-1.000 6.00 O None of these answers is correct 0.008 MABC X 3.000 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES ± 1°QUESTION 2 Question 2 A cross-section of a beam is shown in Figure Q2. If the shear force in this section is V = 125 KN, determine the value and the location of the maximum shear stress in the section. In Figure Q2, a = 30 mm and the origin of the coordinate system is at centroid of the cross section. 7 y= Z= A a AY S= 20 4a mm; mm; O Figure Q2 Answer The vertical coordinate (y-coordinate; the y-axis serves as the axis of symmetry of the cross- section.) and horizontal coordinate (z-coordinate) of the location where the maximum shear stress occurs in the section are ← a The vertical distance from the location where the maximum shear stress occurs in the section to the bottom side (AB cross section can be calculated as Distance = mm (units: mm) 3a Second moment of area The second moment of area employed in the equation to calculate maximum shear stress can be calculated as I₂ = a (units: mm²) Shear stress The second moment of area employed in the equation to calculate maximum shear…