F1354 PF2F2ᎾᎾbP345F1The electric pole is subject to the forces shown. Force F1245 N and force F2 = 310 N with an angle= 20.2°.Determine the moment about point P of all forces. Takecounterclockwise moments to be positive.=Values for dimensions on the figure are given in the followingtable. Note the figure may not be to scale.Variable Valuea2.50 mb11.3 mC13.0 mThe moment about point P is 3,414m.× N-If the moment about point P sums up to be zero. Determinethe distance c while all other values remained the same.1.26m.

Answered: Image /qna-images/answer/b678ae87-9410-46e0-844f-030f7736b285.jpg

Answered: F1 3 5 4 P F2 F2 Ꮎ Ꮎ b P 3 4 5 F1 The…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Consider the tripod in (Figure 1). Figure 1.5m 2m 2m 05m 25m 4m V Part A Determine the magnitude of the moment of the force F = {50i-11j -80k} N about mombor AB of the tripod. Express your answer to three significant figures and include the appropriate units. MAB 222.2 S C Provide Feedback X.10" N•m Submit Previous Answers Request Answer X You have already submitted this answer. Enter a new answer. No credit lost. Try again. ?
The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P
what is the moment about point A? Solve for each individual force about point A
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Consider the bracket shown in Fig-1. If: F1 = 10 N@ 120° • F2 = 75 N@ -90° then, what is the magnitude of the resultant force on the bracket? 8.66 N 66.5 N -75 N 75 N O ON 66.3 N*m 100 N*m O 10 N
Two forces are applied to a hook. Variable F₁₂ Ą a b FR= d FR=( Q= B. values for the figure are given in the following table. Note the figure may not be to scale. value 75 lb 35 lb 2.5 ft B= Y = 4.5 ft 9 ft 1 ft Z a. write each force (F₁,F) as cartesian vectors. b. Find the resultant force FR express as a cartesian vector c. Find the magnitude of the resultant force FR i. a ii. B iii. Y Round your final answers to 3 significant digits/figures. Submit Question → d. Determine the coordinate direction angles of the resultant force FR lb 13/12 a degrees F₂ degrees F₁ degrees A A) lb y e) lb Alb
Fill the table with the correct data and signs (+) (-) please.
Please fill the table with the correct data and signs.
Two forces are acting on the vertical pole, as depicted in the figure and parameter list. Calculate the moment about O for each force. Determine which direction the forces will rotate the pole. 0 BY NO SA 2021 Cathy Zupke parameter L₁ L2 F₁ F₂ 0 e value units 4 ft 10 ft 70 lb 70 70 lb D The moment about O from F₁ The moment about O from F₂ = counterclockwise no moment F₁ L₁ lb-ft lb-ft Choose which direction the pole will tend to rotate: O clockwise O L₂ F₂ 41 5 3
What is the magnitude of the resultant of the applied forces Fr in kN. What is the angle between the resultant force Fr and the negative x axis( measured anti-clockwise from the negative x axis) in degrees.
3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)
A bent tube is attached to a wall with brackets as shown. . A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. → → b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector rDA. Express each of these vectors in Cartesian components. 2013 Michael Swanbom cc 10 BY NC SA g x B A א Z FK с кая b Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a 8 in 12 in с 15 in 36 in h 23 in g 28 in a. F = b. FDA = = ( + k) lb k) lb FIDA = 2 + k) lb

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