A bent tube is attached to a wall with brackets as shown. . A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector rDA Express each of these vectors in Cartesian components. 2013 Michael Swanbom CC BY NC SA g →> h BB Z NE 8° A x F kaz с b Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable a Value 8 in b 12 in с 15 in d 36 in h 23 in 9 28 in a. F = î + k) lb -> b. F||DA = ( î + k) lb →> FIDA = 2+ k) lb

A bent tube is attached to a wall with brackets as shown. . A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector rDA Express each of these vectors in Cartesian components. 2013 Michael Swanbom CC BY NC SA g →> h BB Z NE 8° A x F kaz с b Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable a Value 8 in b 12 in с 15 in d 36 in h 23 in 9 28 in a. F = î + k) lb -> b. F||DA = ( î + k) lb →> FIDA = 2+ k) lb

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter9: Moments And Products Of Inertia Of Areas

Section: Chapter Questions

Problem 9.13P: Figure (a) shows the cross section of a column that uses a structural shape known as W867...

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A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: Fparallel + Fperpendicular = Ftotal 2013 Michael Swanbom BY NC SA d A FK values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. d 78 in h 57 in g 60 in Variable value 13 in 36 in 45 in F|DA = i. k) lb and b. FL DA =
A bent tube is attached to a wall with brackets as shown. . A force of F = 980 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. → → b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector rDA. Express each of these vectors in Cartesian components. 2013 Michael Swanbom cc 10 BY NC SA g x B A א Z FK с кая b Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a 8 in 12 in с 15 in 36 in h 23 in g 28 in a. F = b. FDA = = ( + k) lb k) lb FIDA = 2 + k) lb
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