A bent tube is attached to a wall with brackets as shown.. A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: "parallel + F perpendicular = Ftotal

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of
the tube with direction indicated by the dimensions in the figure.
a.) Determine the force vector F in Cartesian components.
b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector
I DA- Express each of these vectors in Cartesian components.
NOTE: The parallel component of the force is the same as the force along that direction. The
perpendicular component of the force can be found from the relationship:
Fparallel + Fperpendicular = Ftotal
2013 Michael Swanbom
BY NC SA
d
A
FK
values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be
sure to align your cartesian unit vectors with the coordinate axes shown in the figure.
d 78 in h 57 in g 60 in
Variable value
13 in
36 in
45 in
F|DA =
i.
k) lb and
b.
FL DA =
Transcribed Image Text:A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: Fparallel + Fperpendicular = Ftotal 2013 Michael Swanbom BY NC SA d A FK values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. d 78 in h 57 in g 60 in Variable value 13 in 36 in 45 in F|DA = i. k) lb and b. FL DA =
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