A bent tube is attached to a wall with brackets as shown.. A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: "parallel + F perpendicular = Ftotal
A bent tube is attached to a wall with brackets as shown.. A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: "parallel + F perpendicular = Ftotal
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter1: Introduction To Statics
Section: Chapter Questions
Problem 1.74P: It can be show that a plane area may he represented by a vector A=A, where A is the area and ...
Related questions
Question
![A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of
the tube with direction indicated by the dimensions in the figure.
a.) Determine the force vector F in Cartesian components.
b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector
I DA- Express each of these vectors in Cartesian components.
NOTE: The parallel component of the force is the same as the force along that direction. The
perpendicular component of the force can be found from the relationship:
Fparallel + Fperpendicular = Ftotal
2013 Michael Swanbom
BY NC SA
d
A
FK
values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be
sure to align your cartesian unit vectors with the coordinate axes shown in the figure.
d 78 in h 57 in g 60 in
Variable value
13 in
36 in
45 in
F|DA =
i.
k) lb and
b.
FL DA =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5025798a-663c-4f82-a82a-d0677c58328a%2F7a6baa30-13cc-4fd6-b9f0-de598d18c29a%2Fb4ted4w_processed.png&w=3840&q=75)
Transcribed Image Text:A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of
the tube with direction indicated by the dimensions in the figure.
a.) Determine the force vector F in Cartesian components.
b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector
I DA- Express each of these vectors in Cartesian components.
NOTE: The parallel component of the force is the same as the force along that direction. The
perpendicular component of the force can be found from the relationship:
Fparallel + Fperpendicular = Ftotal
2013 Michael Swanbom
BY NC SA
d
A
FK
values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be
sure to align your cartesian unit vectors with the coordinate axes shown in the figure.
d 78 in h 57 in g 60 in
Variable value
13 in
36 in
45 in
F|DA =
i.
k) lb and
b.
FL DA =
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
![International Edition---engineering Mechanics: St…](https://www.bartleby.com/isbn_cover_images/9781305501607/9781305501607_smallCoverImage.gif)
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L
![International Edition---engineering Mechanics: St…](https://www.bartleby.com/isbn_cover_images/9781305501607/9781305501607_smallCoverImage.gif)
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L