A bent tube is attached to a wall with brackets as shown.. A force of F = 450 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector TDA- Express each of these vectors in Cartesian components. 2013 Michael Swanbom (cc 30 BY NC SA

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A bent tube is attached to a wall with brackets as shown. A force of F= 450 lb is applied to the end of
the tube with direction indicated by the dimensions in the figure.
a.) Determine the force vector Fin Cartesian components.
->
b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector
#
TDA- Express each of these vectors in Cartesian components.
2013 Michael Swanbom
XA
BY NC SA
a.
a
b
C
d
h
9
CS
каэ
Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be
sure to align your cartesian unit vectors with the coordinate axes shown in the figure.
Variable Value
7 in
15 in
15 in
35 in
21 in
25 in
b. PDA =
LDA=
9
FK
D
24
i+
2+
j+
lb
k) lb
k) lb
Transcribed Image Text:A bent tube is attached to a wall with brackets as shown. A force of F= 450 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector Fin Cartesian components. -> b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector # TDA- Express each of these vectors in Cartesian components. 2013 Michael Swanbom XA BY NC SA a. a b C d h 9 CS каэ Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value 7 in 15 in 15 in 35 in 21 in 25 in b. PDA = LDA= 9 FK D 24 i+ 2+ j+ lb k) lb k) lb
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