Gentlemen, please help to solve a,b,c as I faced confusing questions about screw jack. Conditions are: screw jack is lifting 3.2 tonnes, screw pitch is 12 mm, diameter of the screw is 5 mm. Coefficient of friction was not given but I think we will need it for total force calculation, lets take it 0.2. a) Calculate horizontal component to move the load - what is ment here by horizontal component? b) Calculate vertical component to move the load - what is ment here by vertical component? c) Total force needed to move the load with a lever of 0.82m d) Velocity ratio (VR=distance by effort/distance by load) Distance by effort (lever)=2 x 3.14 x 0.82 = 5.15m Distance by load = pitch= 12mm= 0.012 m VR=5.15/0.012= approx 429. e) Calculate efficiency. For this we need to have MA (mechanical advantage). It can be calculated when we know total force. Efficiency=Load (3200 x 9.8) / effort
Gentlemen, please help to solve a,b,c as I faced confusing questions about screw jack. Conditions are: screw jack is lifting 3.2 tonnes, screw pitch is 12 mm, diameter of the screw is 5 mm. Coefficient of friction was not given but I think we will need it for total force calculation, lets take it 0.2.
a) Calculate horizontal component to move the load - what is ment here by horizontal component?
b) Calculate vertical component to move the load - what is ment here by vertical component?
c) Total force needed to move the load with a lever of 0.82m
d) Velocity ratio (VR=distance by effort/distance by load)
Distance by effort (lever)=2 x 3.14 x 0.82 = 5.15m
Distance by load = pitch= 12mm= 0.012 m
VR=5.15/0.012= approx 429.
e) Calculate efficiency. For this we need to have MA (
Efficiency=Load (3200 x 9.8) / effort
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