Swing Set: v v v 19 b c d 10in 27in 16in 27in Ra ? w (lb/in) VV e f top bar 10 in Rf 个 2001b 20016 weight of adult sitting Rin T > t = 0.25 in goin Given: • • Swing Set made of steel rated to load capacity of 440 lbs Top bar is treated as a static problem total length = 90 in Louter diameter = 2 in wall thickness = 0.25 in • The 2 people on the swing are not moving just sitting. ↳ each weigh 200 lb • Supports on either side (1) provide only upward reaction force • Self- - weight of the steel beam is a constant weight per unit volume ↳ y = 0.25 16/in³ , хз X4 4 Χς ·w=0.3436b/in cut 1 Cut 2 cut 3 cut'y cuts 100lb Ra = 215 16 1001b 10016 100 lb Re NS I Cut 1 (0 < x < 10 in) ↑ {wx, 215.416 1) M(x1) (Vx₁) Cut 2 (0 2x2 427 in) w(10+82) b a ↑ ↓ 215-41b 1001b +10+ in ·27 in JM(x2) √(x2) > x2 cut 3 (0 < x 34 16 in) 54(x3+37) a b ↓ c 100 16 215-416 1001b Ho+27+ > x3 ↓5 M(x(3) V(23) Cut 5 (0 < x <27in) SW (R 5+ 10) Cut 4 (0 < x < 10 in) (wxy ные v(x4) хи '215.4 lb مرد M(x5) √(25) Exs 10016 10 215.416 in

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The question has been set up with all the cuts needed to accurately derive expressions for V(x) and M(x). Using the cuts free body diagrams set up below, derive expressions for V(x) and M(x). If you use the method of cuts then validate your answers using calculus or vice versa. 

Swing Set:
v v v
19
b
c
d
10in
27in
16in
27in
Ra
? w (lb/in)
VV
e
f
top bar
10 in
Rf
个
2001b
20016
weight of adult sitting
Rin
T
> t = 0.25 in
goin
Given:
•
• Swing Set made of steel rated to load capacity of 440 lbs
Top bar is treated as a static problem
total length = 90 in
Louter diameter = 2 in
wall thickness = 0.25 in
• The 2 people on the swing are not moving just sitting.
↳ each weigh 200 lb
• Supports on either side (1) provide only upward reaction force
• Self-
- weight of the steel beam is a constant weight per unit volume
↳ y = 0.25 16/in³
Transcribed Image Text:Swing Set: v v v 19 b c d 10in 27in 16in 27in Ra ? w (lb/in) VV e f top bar 10 in Rf 个 2001b 20016 weight of adult sitting Rin T > t = 0.25 in goin Given: • • Swing Set made of steel rated to load capacity of 440 lbs Top bar is treated as a static problem total length = 90 in Louter diameter = 2 in wall thickness = 0.25 in • The 2 people on the swing are not moving just sitting. ↳ each weigh 200 lb • Supports on either side (1) provide only upward reaction force • Self- - weight of the steel beam is a constant weight per unit volume ↳ y = 0.25 16/in³
, хз
X4
4
Χς
·w=0.3436b/in
cut 1
Cut 2
cut 3
cut'y
cuts
100lb
Ra = 215 16
1001b
10016
100 lb
Re NS I
Cut 1 (0 < x < 10 in)
↑
{wx,
215.416
1) M(x1)
(Vx₁)
Cut 2 (0 2x2 427 in)
w(10+82)
b
a
↑
↓
215-41b 1001b
+10+
in
·27
in
JM(x2)
√(x2)
> x2
cut 3 (0 < x 34 16 in)
54(x3+37)
a
b
↓
c
100 16
215-416 1001b
Ho+27+
> x3
↓5 M(x(3)
V(23)
Cut 5 (0 < x <27in)
SW (R 5+ 10)
Cut 4 (0 < x < 10 in)
(wxy
ные
v(x4)
хи
'215.4 lb
مرد
M(x5)
√(25)
Exs
10016
10
215.416
in
Transcribed Image Text:, хз X4 4 Χς ·w=0.3436b/in cut 1 Cut 2 cut 3 cut'y cuts 100lb Ra = 215 16 1001b 10016 100 lb Re NS I Cut 1 (0 < x < 10 in) ↑ {wx, 215.416 1) M(x1) (Vx₁) Cut 2 (0 2x2 427 in) w(10+82) b a ↑ ↓ 215-41b 1001b +10+ in ·27 in JM(x2) √(x2) > x2 cut 3 (0 < x 34 16 in) 54(x3+37) a b ↓ c 100 16 215-416 1001b Ho+27+ > x3 ↓5 M(x(3) V(23) Cut 5 (0 < x <27in) SW (R 5+ 10) Cut 4 (0 < x < 10 in) (wxy ные v(x4) хи '215.4 lb مرد M(x5) √(25) Exs 10016 10 215.416 in
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