(a) A helical spring is made from a wire of 8 mm diameter and has outside diameter of 80 mm. If the permissible shear stress is 400 MPa and modulus of rigidity 80 kN/mm?, find the axial load which the spring can carry and the deflection per active turn. ) Neglecting the effect of curvature, and ii) Considering the effect of curvature. (b) Design a helical compression spring for a macimum load of 1000 N for a deflection of 30 mm using the value of spring index as 7. The maximum permissible shear stress for spring wire is 400 MPa and modulus of rigidity is 80 kN/mm². 4C -1. 0.615 Take Wahl's factor, where C = Spring tndex. 4C – 4

Elements Of Electromagnetics
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Question .03
Helical springs are made up of wire coiled in the form of helix and is primarily intended for compressive
or tensile loads.
Consider a helical compression spring made of circular wire and subjected to an axial load W,
as shown in Figure Q3
Let
D = Mean diameter of the spring coil,
d = Diameter of the spring wire,
n = Number of active coils,
G = Modulus of rigidity for the spring material,
W = Axial load on the spring,
T = Maximum shear stress induced in the wire,
C = Spring index = Dld,
p = Pitch of the coils, and
8 = Deflection of the spring, as a result of an axial load W.
(a) Axially loaded helical spring.
Figure Q3 Axially loaded helical spring
Spring index,
C =
d
W = Axial load, and
8/n = Deflection per active turn.
Let
Transcribed Image Text:Question .03 Helical springs are made up of wire coiled in the form of helix and is primarily intended for compressive or tensile loads. Consider a helical compression spring made of circular wire and subjected to an axial load W, as shown in Figure Q3 Let D = Mean diameter of the spring coil, d = Diameter of the spring wire, n = Number of active coils, G = Modulus of rigidity for the spring material, W = Axial load on the spring, T = Maximum shear stress induced in the wire, C = Spring index = Dld, p = Pitch of the coils, and 8 = Deflection of the spring, as a result of an axial load W. (a) Axially loaded helical spring. Figure Q3 Axially loaded helical spring Spring index, C = d W = Axial load, and 8/n = Deflection per active turn. Let
*** Consider neglecting the effect of curvature (Direct shear stress due to the load W)
*** Design of helical compression spring.
i)
Mean diameter of the spring coil
Shear stress factor, Ks,
D= C.d
Kg = 1+
20
Outer diameter of the spring coil, 0.15
Maximum shear stress induced in the wire (t)
Do = D+d
8 W.D
Number of turns of the coil, n’,
n' =n+2
= Ks
ii)
Deflection of the spring,
8 W.D.n
8 =
G.d*
Free length of the spring,
= n'd + 8 + 0.158
iii)
Deflection per active turn,
iv)
Pitch of the coil,
8 W.D
G.d“
Free length
n' -1
*** Considering the effect of curvature (Stress due to curvature of wire)
Wahl's stress factor,
(a) A helical spring is made from a wire of 8 mm diameter and has outside diameter of 80
4С - 1
0.615
тт.
K =
+
4С - 4
If the permissible shear stress is 400 MPa and modulus of rigidity 80 kN/mm?, find
the axial load which the spring can carry and the deflection per active turn.
Maximum shear stress induced in the wire (t)
8W.C
= KX
n d?
i) Neglecting the effect of curvature, and
ii) Considering the effect of curvature.
Deflection of the spring,
8 W.D.n
8 =
G.d*
Deflection per active turn,
8 W.D
G.d
(b) Design a helical compression spring for a maximum load of 1000 N for a deflection of
30 mm using the value of spring index as 7.
The maximum permissible shear stress for spring wire is 400 MPa and modulus of
rigidity is 80 kN/mm?.
4С -1
0.615
Take Wahl's factor,
K =
where C = Spring index.
4С - 4
Transcribed Image Text:*** Consider neglecting the effect of curvature (Direct shear stress due to the load W) *** Design of helical compression spring. i) Mean diameter of the spring coil Shear stress factor, Ks, D= C.d Kg = 1+ 20 Outer diameter of the spring coil, 0.15 Maximum shear stress induced in the wire (t) Do = D+d 8 W.D Number of turns of the coil, n’, n' =n+2 = Ks ii) Deflection of the spring, 8 W.D.n 8 = G.d* Free length of the spring, = n'd + 8 + 0.158 iii) Deflection per active turn, iv) Pitch of the coil, 8 W.D G.d“ Free length n' -1 *** Considering the effect of curvature (Stress due to curvature of wire) Wahl's stress factor, (a) A helical spring is made from a wire of 8 mm diameter and has outside diameter of 80 4С - 1 0.615 тт. K = + 4С - 4 If the permissible shear stress is 400 MPa and modulus of rigidity 80 kN/mm?, find the axial load which the spring can carry and the deflection per active turn. Maximum shear stress induced in the wire (t) 8W.C = KX n d? i) Neglecting the effect of curvature, and ii) Considering the effect of curvature. Deflection of the spring, 8 W.D.n 8 = G.d* Deflection per active turn, 8 W.D G.d (b) Design a helical compression spring for a maximum load of 1000 N for a deflection of 30 mm using the value of spring index as 7. The maximum permissible shear stress for spring wire is 400 MPa and modulus of rigidity is 80 kN/mm?. 4С -1 0.615 Take Wahl's factor, K = where C = Spring index. 4С - 4
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