Determination of vertical displacement of Mid-Term Project pipe assembly Find the vertical displacement at position C in the figure. Pipe inner diameter: 40 mm, Pipe outer diameter: 60 mm 800 mm Material: A-36 Steel 600 N -By the force 600N, the AB part of the pipe is subjected to bending and torsional loads. BC part is subjected to bending load. -The energy equation by this load is as follows. Energy equation by torsional load: 400 mm T°dx (U), = : 2GJ Problem: Energy equation by bending load a) First, draw a free body diagram and the AB part Of the bending /torsional load of the BC and Derive the bending load equation. So By applying it to the high energy formula, Save energy and make it the same as external energy Release to find the vertical displacement. b) Creo modeling and structural analysis M²dx (U), 2EI -The sum of the internal energy of 2 energy is as follows. U=U: +Ub -Due to energy conservation, the sum of the internal energy U is the external due to the load 600 NGet the vertical displacement at position C It is equal to the magnitude of negative energy. U= (½)PA = (%½)(600)A -> -Vertical displacement A =U /300 Compare it with the value obtained in a).

Determination of vertical displacement of Mid-Term Project pipe assembly Find the vertical displacement at position C in the figure. Pipe inner diameter: 40 mm, Pipe outer diameter: 60 mm 800 mm Material: A-36 Steel 600 N -By the force 600N, the AB part of the pipe is subjected to bending and torsional loads. BC part is subjected to bending load. -The energy equation by this load is as follows. Energy equation by torsional load: 400 mm T°dx (U), = : 2GJ Problem: Energy equation by bending load a) First, draw a free body diagram and the AB part Of the bending /torsional load of the BC and Derive the bending load equation. So By applying it to the high energy formula, Save energy and make it the same as external energy Release to find the vertical displacement. b) Creo modeling and structural analysis M²dx (U), 2EI -The sum of the internal energy of 2 energy is as follows. U=U: +Ub -Due to energy conservation, the sum of the internal energy U is the external due to the load 600 NGet the vertical displacement at position C It is equal to the magnitude of negative energy. U= (½)PA = (%½)(600)A -> -Vertical displacement A =U /300 Compare it with the value obtained in a).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: The compound shaft shown in the figure consists of two steel [G = 80 GPa] pipe segments. The shaft…

A: Given Data: The modulus of rigidity of steel is, G=80 GPa=80 GPa×1000 MPaGPa=80000 MPa. The outside…

Q: Determine the horizontal displacement of point D in the system shown in the figure using…

A: The partial derivative of the total strain energy of a structure with respect to a specific force…

Q: Q1: The shaft shown in Figure (1) is supported by two bearings and carries two V-belt sheaves.

Q: An hydraulic actuator (see Fig 3) is made from pressed mild steel has a Young's Modulus of 205GPa…

A: Given Internal pressure Pi=75 bar Bending moment M = 25 Nm External diameter D0= 55 mm Thickness t…

Q: cays below 300 °F. nce limit for this steel with a reliability in the range resulting in a gradient…

Q: Given is a thin-walled tube with the following data: Wall thickness- 2mm ABC is a sector with a…

Q: The compound shaft shown in the figure consists of two steel [G = 80 GPa] pipe segments. The shaft…

A: Given Data:The modulus of rigidity of steel is..The outside diameter of segment 1 is..The wall…

Q: Q.3)A cylindrical compound shaft consists of two pipes as shown below. Pipe (1) has an outside…

A: Given:outer diameter of pipe 1, do=6.25 inchthickness, t=0.5 inchso inner diameter of pipe…

Q: A hydraulic punch press is used to punch a slot in a 0.5 in. thick plate, as illustrated in the…

Q: 2. A pipe of length L is lifted by a sling, as shown in the figure. The outer diameter of the pipe…

A: Given data:

Q: A motor drives a shaft at 56 Hz and delivers 11 kW of power (see figure). 56 Hz 11 kW (a) If the…

Q: Parvinbhai

A: The objective of this problem is to draw the shear force and bending moment diagrams for a car jack…

Q: For the beam illustrated in the figure, find the locations and magnitudes of the maximum tensile…

Q: A countershaft carrying two V-belt pulleys is shown in the figure. Pulley A receives power from a…

A: A countershaft carrying two V-belt pulleys is shown in the figure. Pulley A receives power from a…

Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

100%

Determination of vertical displacement of Mid-Term Project pipe assembly
Find the vertical displacement at position C in the figure.
800 mm
Pipe inner diameter: 40 mm, Pipe outer diameter: 60 mm
Material: A-36 Steel
600 N
B.
-By the force 600N, the AB part of the pipe is subjected to bending and torsional loads.
BC part is subjected to bending load.
-The energy equation by this load is as follows.
Energy equation by torsional load:
400 mm
T²dx
(U), =
2GJ
Problem:
Energy equation by bending load
a) First, draw a free body diagram and the AB part
Of the bending/torsional load of the BC and
Derive the bending load equation. So
M²dx
(U) =
2EI
By applying it to the high energy formula,
Save energy and make it the same as external energy
Release to find the vertical displacement.
-The sum of the internal energy of 2 energy is as follows.
U=U: +Ub
b) Creo modeling and structural analysis
-Due to energy conservation, the sum of the internal energy U is the external due to the load 600 NGet the vertical displacement at position C
It is equal to the magnitude of negative energy.
U= (4)PA = (4)(600)A ->
Compare it with the value obtained in a).
-Vertical displacement A=U /300

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Find the max shear stress in a 200mm tall, 150mm wide rectangular cross section using the appropriate reduced shear stress equation. Assume Vmax = 12kN. Find the max shear stress in a W12x50 cross-section using the appropriate estimated shear stress equation. Assume Vmax = 236kips. Find the max shear stress in bending in the cross section below if Vmax = 10 kips. 10" Flange 2" Web 2" 8" Flange 2" 10" • Identify where in the cross section the max shear will occur. • Determine the thickness of the cross-section at the location you wish to find shear stress. • Calculate the Ix for the shape (assume bending in the x with most basic beams). • Calculate Q by dividing the section into two pieces at the point you want shear stress. Select one of the pieces (either will work), I picked the top piece. • Use the Shear Stress equation to determine the requested stress. • Compare you answer: Max shear stress = at the center of the cross section.
Practice Problem 2: (3) P = 0.0400 T= 28.98 X = 0.913 H = 2342.64 (9) P = 1.0135 T= 22 Sub = 78.0 H = 92.31 -> H*= -204.85 H*= -2455.18 M = 103.5 M = 5494.5 3 (8) P= 1.0135 T= 12 Sub = 88.0 H = 50.47 H*= -2497.02 M = 5494.5 P[bar] T[C] H[kJ/kg] H*[kJ/kg] M[kg/s] Data for the above Schematic Calculate: a. The heat rejected by the steam in kW. b. Heat rejected in the Cooling water in kW. Find LMTD in °C and in °F. d. If U=2500 W/(m2.°C), find the surface area of the pipes. С.
Please full solution with big and clear handwriting
Materials Mechanics II
2. [-/1 Points] DETAILS GGMECHMAT9 3.7.006. The drive shaft for a truck (outer diameter 80 mm and inner diameter 25 mm) is running at 2,300 rpm (see figure). 2,300 гpm 80 mm 25 mm 80 mm (a) If the shaft transmits 150 kW, what is the maximum shear stress in the shaft? (Enter the magnitude in MPa.) MPа (b) If the allowable shear stress is 30 MPa, what is the maximum power (in kW) that can be transmitted? kW
A countershaft carrying two V-belt pulleys is shown in the figure. Pulley A receives power from a motor through a belt with the belt tensions shown. The power is transmitted through the shaft and delivered to the belt on pulley B. Assume the belt tension on the loose side at B is 15 percent of the tension on the tight side. For the steel countershaft shown in the figure below, find the deflection and slope of the shaft at point A. Use superposition with the deflection equations in Table A-9. Assume the bearings constitute simple supports. In the figure shown below, Tx= 330 lbf, Ty= 50 lbf, and the diameter of the shaft (dshaft) = 1.07 in. y Tx dshaft 6 dia. Ty 8 dia. The deflection at point A is The slope at point A is rad. in.
Given inner diameter=45mm thickness=6mm I=200*10^-6 G=30Gpa pressure inside=1.4Mpa 1.the hoop stress due to inside pressure alone? 2.The normal stress at a due to bending moment alone ? 3.The shear stress at a due to torsion alone is ? 4.the shear stress at a due to shear alone? 5.the maximum shear stress due to shear alone? 6.the total length of the tank is 1700mm..the deflection of point D is?
For the beam illustrated in the figure, find the locations and magnitudes of the maximum tensile bending stress due to M and the maximum shear stress due to V. Parameters are a = 310 mm, b= 135 mm, c = 20 mm, h = 40 mm, and F= 4350 N. a mm FN bmm The moment of inertia is C mm hmm |x105 mm4. The maximum tensile bending stress due to Mis The maximum shear stress due to Vis MPa. MPa.
Values are m= 360mm n= 375mm q= 24mm r= 18mm P= 0.6kN
A solid shaft made from AISI 1040 cold-drawn steel is used to carry two V-belt, as shown in the Fig. 3. Pulley A receives power from a motor through a belt, with the belt tensions shown in Fig. 3. The power is transmitted through the shaft and delivered to the belt through pulley B. Assume the belt tension on the loose side is 10 percent of the tension on the tight side.
A petrol engine inlet valve is spring-loaded. The valve opens at 360 N closes at 220 N, while the corresponding lengths of springs when it is open is 41 mm and when it is closed is 49 mm. The maximum inside diameter of the spring is 25 mm. Assume the shear yield strength in steel as 400 MPa, shear ultimate strength is 643.2 MPa and shear modulus as 80 kN/mm². Assume the helical compression spring has squared and ground ends, minimum factor of safety, n = 1.5 and spring index, C = 5. Determine for shot-peened wires a) initial compression b) coil diameter d using Zimmerli data, Goodman theory and Langer theory. Select standard size of Washburn & Moen wire c) helical diameter D d) number of actual turns, Na and total turns, Nt e) free length
Consider the special steel spring in the illustration. (a) Find the pitch, solid height, and number of active turns. (b) Find the spring rate. Assume the material is A227 HD steel. (c) Find the force Fs required to close the spring solid. (d) Find the shear stress in the spring due to the force Fs. 150mm 75mm -e Smm