Reagent M.w Q Mmol MEQ Aldehyde 151.12g/mol 1.057 7.00 1.01 ketone 150.7g/mol 1.036 6.90 1 NaOH 39.997g/mol 200mg catalyst Balanced equation: 3. M 1.961 g maleic anhydride, 0.02001 I Y mol maleic anhydende - 0.02mol 98.00 maleic anhydride theoretical mol MA I mot step! NP x x * 221.07 & step! 3.61 Imol MA I mol step! Actual Reset S 4.40N 4.42341 Step M theoretical #204 4.42361 43.611gx/mol 1000% 854 305 yold 81.6% step 1 T = 0.01433mol 22107 5.0.014 33 mol x (mol = 0.01633 (Step 2 product) Imol 0.01633molx 20741 = 3.390g (theoretical) Imol 1. Shel gactual gactual x 100% 46.39% % yield (step2 product). 2.35g (theoretical

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter9: Aqueous Solutions And Chemical Equilibria
Section: Chapter Questions
Problem 9.8QAP
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help with a balanced equation using the info in the chart, ive added an example of how my pratice work,use info in chart. make like example provided on paper

Reagent
M.w
Q
Mmol
MEQ
Aldehyde
151.12g/mol
1.057
7.00
1.01
ketone
150.7g/mol
1.036
6.90
1
NaOH
39.997g/mol
200mg
catalyst
Balanced equation:
Transcribed Image Text:Reagent M.w Q Mmol MEQ Aldehyde 151.12g/mol 1.057 7.00 1.01 ketone 150.7g/mol 1.036 6.90 1 NaOH 39.997g/mol 200mg catalyst Balanced equation:
3.
M
1.961 g maleic anhydride,
0.02001
I
Y
mol maleic anhydende - 0.02mol
98.00 maleic anhydride
theoretical
mol MA
I mot step!
NP
x
x
*
221.07 & step!
3.61
Imol MA
I mol step!
Actual
Reset S
4.40N
4.42341
Step
M
theoretical #204
4.42361
43.611gx/mol
1000%
854 305
yold
81.6%
step 1
T
= 0.01433mol
22107
5.0.014 33 mol x (mol
= 0.01633 (Step 2 product)
Imol
0.01633molx
20741
=
3.390g (theoretical)
Imol
1. Shel gactual
gactual x 100% 46.39% % yield (step2 product).
2.35g (theoretical
Transcribed Image Text:3. M 1.961 g maleic anhydride, 0.02001 I Y mol maleic anhydende - 0.02mol 98.00 maleic anhydride theoretical mol MA I mot step! NP x x * 221.07 & step! 3.61 Imol MA I mol step! Actual Reset S 4.40N 4.42341 Step M theoretical #204 4.42361 43.611gx/mol 1000% 854 305 yold 81.6% step 1 T = 0.01433mol 22107 5.0.014 33 mol x (mol = 0.01633 (Step 2 product) Imol 0.01633molx 20741 = 3.390g (theoretical) Imol 1. Shel gactual gactual x 100% 46.39% % yield (step2 product). 2.35g (theoretical
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