Part 1: First Halfway point Ka₁ = 2.34x10 Second Halfway Point: Ka, = 631×10' Moles of NaOH at the Equivalence Point First Equivalence Point Second Equivalence Point 1.1826 x 10 mol 1444 107 Moles of KHP at the Equivalence Point First Equivalence Point Same as the moles of NaOH¸ = 1.1826 × 10-ª mol Second Equivalence Point: Same as the moles of NaOH= 2.444 × 107 Molar mass of KHP =204.12 g/mol Mass of KHP used at first equivalence 2.45 x 10 g Mass of KHP used at first equivalence = 4.99x10 g Part 2: First Halfway point: Ka₁ = 2.34x10 Second Halfway Point: Ka, 631-10 Males of NaOH at the Equivalence Point First Equivalence Point 1.1826 x 10 mol Second Equivalence Point 2.444 x 10 Moles of KHP at the Equivalence Point First Equivalence Point Same as the moles of NaOH, = 1.1826 x 10 mol Second Equivalence Point: Same as the moles of NaOH= 2.444 x 10- Molar mass of KHP=204.22 g/mol Mass of KHP used at first equivalence = 1.1826 x 10' mol

Part 1: First Halfway point Ka₁ = 2.34x10 Second Halfway Point: Ka, = 631×10' Moles of NaOH at the Equivalence Point First Equivalence Point Second Equivalence Point 1.1826 x 10 mol 1444 107 Moles of KHP at the Equivalence Point First Equivalence Point Same as the moles of NaOH¸ = 1.1826 × 10-ª mol Second Equivalence Point: Same as the moles of NaOH= 2.444 × 107 Molar mass of KHP =204.12 g/mol Mass of KHP used at first equivalence 2.45 x 10 g Mass of KHP used at first equivalence = 4.99x10 g Part 2: First Halfway point: Ka₁ = 2.34x10 Second Halfway Point: Ka, 631-10 Males of NaOH at the Equivalence Point First Equivalence Point 1.1826 x 10 mol Second Equivalence Point 2.444 x 10 Moles of KHP at the Equivalence Point First Equivalence Point Same as the moles of NaOH, = 1.1826 x 10 mol Second Equivalence Point: Same as the moles of NaOH= 2.444 x 10- Molar mass of KHP=204.22 g/mol Mass of KHP used at first equivalence = 1.1826 x 10' mol

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.24QAP

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[OH-] = = [+H] M M
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