Consider the weak bases below and their Kp values: Ky = 1.8 x 10-5 Kp = 5.6 x 10-4 10-9 NH3 C2H5NH2 C5H5N Kp = 1.7 x Arrange the conjugate acids of these weak bases in order of increasing acid strength. O CsH;NH*< NH,*< C2H5NH3* O C2H;NH,*= NH4* = C5H;NH* O C,H;NH;*< NH,*< C5H5NH* NH,*< C2H5NH3*

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Consider the weak bases below and their \( K_b \) values:

- \( \text{NH}_3 \) \hspace{0.2cm} \( K_b = 1.8 \times 10^{-5} \)
- \( \text{C}_2\text{H}_5\text{NH}_2 \) \hspace{0.2cm} \( K_b = 5.6 \times 10^{-4} \)
- \( \text{C}_5\text{H}_5\text{N} \) \hspace{0.2cm} \( K_b = 1.7 \times 10^{-9} \)

**Arrange the conjugate acids of these weak bases in order of increasing acid strength.**

- \( \bigcirc \) \( \text{C}_5\text{H}_5\text{NH}^+ < \text{NH}_4^+ < \text{C}_2\text{H}_5\text{NH}_3^+ \)

- \( \bigcirc \) \( \text{C}_2\text{H}_5\text{NH}_3^+ = \text{NH}_4^+ = \text{C}_5\text{H}_5\text{NH}^+ \)

- \( \bigcirc \) \( \text{C}_2\text{H}_5\text{NH}_3^+ < \text{NH}_4^+ < \text{C}_5\text{H}_5\text{NH}^+ \)

- \( \bigcirc \) \( \text{NH}_4^+ < \text{C}_2\text{H}_5\text{NH}_3^+ < \text{C}_5\text{H}_5\text{NH}^+ \)
Transcribed Image Text:Consider the weak bases below and their \( K_b \) values: - \( \text{NH}_3 \) \hspace{0.2cm} \( K_b = 1.8 \times 10^{-5} \) - \( \text{C}_2\text{H}_5\text{NH}_2 \) \hspace{0.2cm} \( K_b = 5.6 \times 10^{-4} \) - \( \text{C}_5\text{H}_5\text{N} \) \hspace{0.2cm} \( K_b = 1.7 \times 10^{-9} \) **Arrange the conjugate acids of these weak bases in order of increasing acid strength.** - \( \bigcirc \) \( \text{C}_5\text{H}_5\text{NH}^+ < \text{NH}_4^+ < \text{C}_2\text{H}_5\text{NH}_3^+ \) - \( \bigcirc \) \( \text{C}_2\text{H}_5\text{NH}_3^+ = \text{NH}_4^+ = \text{C}_5\text{H}_5\text{NH}^+ \) - \( \bigcirc \) \( \text{C}_2\text{H}_5\text{NH}_3^+ < \text{NH}_4^+ < \text{C}_5\text{H}_5\text{NH}^+ \) - \( \bigcirc \) \( \text{NH}_4^+ < \text{C}_2\text{H}_5\text{NH}_3^+ < \text{C}_5\text{H}_5\text{NH}^+ \)
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