The equilibrium expression for the hydrolysis of a weak base, A™, in water is: OK=[A]/[OH-][H3O+] K₁ = [OH-][HA]/[A¯][H3O+] OK = [OH-][A]/[HA] O Kb = [OH-][H3O*]/[A-] K₂ = [OH-][HA]/[A]

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Chapter1: Chemical Foundations
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The equilibrium expression for the hydrolysis of a weak base, A™, in water is:
OK=[A]/[OH-][H3O+]
K₁ = [OH-][HA]/[A-][H30*]
OK₂= [OH-][A-]/[HA]
O K₂ = [OH-][H3O*]/[A-]
K₁ = [OH-][HA]/[A-]
Transcribed Image Text:The equilibrium expression for the hydrolysis of a weak base, A™, in water is: OK=[A]/[OH-][H3O+] K₁ = [OH-][HA]/[A-][H30*] OK₂= [OH-][A-]/[HA] O K₂ = [OH-][H3O*]/[A-] K₁ = [OH-][HA]/[A-]
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