Identify the reactant that is a Brønsted-Lowry acidand the reactant that is a Brønsted-Lowry base ineach of the following:Part C2-CO3² (aq) + H₂O = HCO3(aq) + OH-(aq)H₂O is the acid (proton donor); CO3² is the base (proton acceptor).H₂O is the acid (proton acceptor); CO² is the base (proton donor).O CO3²- is the acid (proton acceptor); H₂O is the base (proton donor).O CO² is the acid (proton donor); H₂O is the base (proton acceptor).SubmitPart BRequest AnswerH₂SO4 (aq) + H₂O(1)→ H3O+ (aq) + HSO4 (aq)O H₂O is the acid (proton donor); H₂SO4 is the base (proton acceptor).O H₂SO4 is the acid (proton acceptor); H₂O is the base (proton donor).O H₂SO4 is the acid (proton donor); H₂O is the base (proton acceptor).O H₂O is the acid (proton acceptor); H₂SO4 is the base (proton donor).CH3-COO (aq) + H3O+ (aq) = H₂O(1) + CH3-COOH(aq)CH3-COO is the acid (proton acceptor); H3O+ is the base (proton donor).O H3O+ is the acid (proton donor); CH3-COO is the base (proton acceptor).O H3O+ is the acid (proton acceptor); CH3-COO is the base (proton donor).CH3-COO is the acid (proton donor); H3O+ is the base (proton acceptor).

Answered: Identify the reactant that is a…

Identify the reactant that is a Brønsted-Lowry acid and the reactant that is a Brønsted-Lowry base in each of the following:

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Identify the reactant that is a Brønsted-Lowry acid
and the reactant that is a Brønsted-Lowry base in
each of the following:
Part C
2-
CO3² (aq) + H₂O = HCO3(aq) + OH-(aq)
H₂O is the acid (proton donor); CO3² is the base (proton acceptor).
H₂O is the acid (proton acceptor); CO² is the base (proton donor).
O CO3²- is the acid (proton acceptor); H₂O is the base (proton donor).
O CO² is the acid (proton donor); H₂O is the base (proton acceptor).
Submit
Part B
Request Answer
H₂SO4 (aq) + H₂O(1)→ H3O+ (aq) + HSO4 (aq)
O H₂O is the acid (proton donor); H₂SO4 is the base (proton acceptor).
O H₂SO4 is the acid (proton acceptor); H₂O is the base (proton donor).
O H₂SO4 is the acid (proton donor); H₂O is the base (proton acceptor).
O H₂O is the acid (proton acceptor); H₂SO4 is the base (proton donor).
CH3-COO (aq) + H3O+ (aq) = H₂O(1) + CH3-COOH(aq)
CH3-COO is the acid (proton acceptor); H3O+ is the base (proton donor).
O H3O+ is the acid (proton donor); CH3-COO is the base (proton acceptor).
O H3O+ is the acid (proton acceptor); CH3-COO is the base (proton donor).
CH3-COO is the acid (proton donor); H3O+ is the base (proton acceptor).

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