A 25.00 mL sample containing an unknown amount of Al³ + and Pb² + required 15.73 mL of 0.05631 M EDTA to reach the endpoint. A 50.00 mL sample of the unknown was then treated with F to mask the A1³ +. To the 50.00 mL sample, 25.00 mL of0.05631 M EDTA was added. The excess EDTA was then titrated with 0.02203 M Mn² +. A total of 25.9 mL was required toreach the methylthymol blue end point. Determine pAl³ + and pPb² + in the unknown sample.

Given: V=25.00mL;VEDTA(1)=15.73mL;[EDTA]=0.05631MVEDTA(2)=25.00mL;VMn2+=25.90mL;[Mn2+]=0.02203M…

Answered: A 25.00 mL sample containing an unknown…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.3QAP

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