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- 2. Our knowledge of chair conformations allows us to use them to determine a great deal about a reaction's mechanism. In particular, using a t-butyl group to 'fix' a cyclohexane in a single conformation can help us learn about the spatial requirements and energetics of a reaction. Consider the following two reaction products: CN 1) NaCN 2) H+ OH 1) NaBH4 2) H3O+ OH Group -H -CN A Value (kcal/mol) Defined as 0 0.2 kcal/mol -OH 1.0 kcal/mol c. For any products that do have the most stable conformation, does our understanding of the mechanism allow for ‘thermodynamic control'? d. If one of the products is not the most stable, can you explain the observed product based on ‘kinetic control'? (Does the most easily formed transition state result in the observed product?) Consider the chair-like conformation of the starting material.[References] The two alkenes below react with HI at different rates. CH3 CH3CH=CHCH3 and CH;ċ=CHCH3 Draw the structural formula of the MAJOR product formed by the alkene having the HIGHER reaction rate. You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. C P opy aste Previous Next ChemDoodle®TRUE OR FALSE i. A =C-Br bond is more polar than a -C-Br bond. ii. A bromonium ion can undergo hydride or methyl shift to produce a more stable carbocation. iii. The two conformers of cis-1,3-diaminocyclohexane will have equal stability.
- Carbocations rearrange with some ease. An example of this is shown below. Indicate, with the corresponding arrows, how this process occurs. The carbocation 2 is more stable than 1, why is this? Explain it using (drawing) structures.Help please3. Write down the mechanism for the following reaction and predict which of the two possible products will be formed in the greatest yield (2nd and 3rd carbocation). Write down the structures of the two possible products and explain your answer. CH3CH = CHCH2 CH2 CH3 + HBr
- МЕСНANISMS 1,2-epoxy-1-methylcyclopentane undergoes both acid-catalyzed and base-catalyzed opening of the epoxide ring to form two different products. > Using ethanol as the solvent and an appropriate acid, show the steps in the acid catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). > Using ethanol as the solvent and an appropriate base, show the steps in the base- catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). 1,2-epoxy-1-methylcyclopentane CH3Arrange the following alkenes in order of increasing stability (least stable to most stable). I3D II IV O IV < III < II < | O II < IV < |I < | O IV < || < |II < | O III < II < | < IV O Il < IV < I < III MacBook Prob Assuming that halogens add to alkynes in the same manner that they add to alkenes, write a mechanism for the reaction step below. Use curved arrows to show electron reorganization. Arrow-pushing Instructions H3C C↔X ™ Br: CH3 Br