Calculate the pH of a 0.154 M solution of ethylenediamine (H,NCH2CH2NH2). The pKa values for the acidic form of thylenediamine (H3NCH2CH2NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = 11.51 Correct Answer Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H2NCH2CH2NH] = 4.12 x10-3 Incorrect Answer 7.05 x10 -8 [HNCH2CH2NH] = Correct Answer M M
Calculate the pH of a 0.154 M solution of ethylenediamine (H,NCH2CH2NH2). The pKa values for the acidic form of thylenediamine (H3NCH2CH2NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = 11.51 Correct Answer Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H2NCH2CH2NH] = 4.12 x10-3 Incorrect Answer 7.05 x10 -8 [HNCH2CH2NH] = Correct Answer M M
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section16.10: The Lewis Concept Of Acids And Bases
Problem 2.3ACP
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![Calculate the pH of a 0.154 M solution of ethylenediamine (H,NCH2CH2NH2). The pKa values for the acidic form of
thylenediamine (H3NCH2CH2NH) are 6.848 (pKa1) and 9.928 (pKa2).
pH =
11.51
Correct Answer
Calculate the concentration of each form of ethylenediamine in this solution at equilibrium.
[H2NCH2CH2NH] =
4.12 x10-3
Incorrect Answer
7.05 x10
-8
[HNCH2CH2NH] =
Correct Answer
M
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F60472e4e-bd24-4f7b-ae52-b533b6d6aa09%2F1ef289aa-fc39-49ef-bd82-d262c61a31b1%2F2xy95k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the pH of a 0.154 M solution of ethylenediamine (H,NCH2CH2NH2). The pKa values for the acidic form of
thylenediamine (H3NCH2CH2NH) are 6.848 (pKa1) and 9.928 (pKa2).
pH =
11.51
Correct Answer
Calculate the concentration of each form of ethylenediamine in this solution at equilibrium.
[H2NCH2CH2NH] =
4.12 x10-3
Incorrect Answer
7.05 x10
-8
[HNCH2CH2NH] =
Correct Answer
M
M
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